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4 years ago

Which two layers of Earth are mainly composed of iron and nickel? inner core outer core lower mantle upper mantle crust

Physics

2 answers:

Arada [10]4 years ago

8 0

Outer core and the inner core I believe.

stich3 [128]4 years ago

3 0

Inner core and outer core

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Which of the following is NOT an example of work?

marysya [2.9K]

I think the answer is c.holding a tray in the cafeteria line

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4 years ago

What is the wavelength of an fm radio signal that has a frequency of 91.7 mhz?

Digiron [165]

Answer:

The wavelength of the radio wave will be 3.271 m

Explanation:

We have given frequency of the radio signal $f=91.7MhZ=91.7\times 10^6Hz$

Speed of the light $c=3\times 10^8m/sec$

We have to find the wavelength of the radio signal

We know that wavelength is given by $\lambda =\frac{c}{f}=\frac{3\times 10^8}{91.7\times 10^6}=3.271m$

So the wavelength of the radio wave will be 3.271 m

3 0

3 years ago

A lowly high diver pushes off horizontally with a speed of 2.00 m/s from the platform edge 10.0 m above the surface of the water

VladimirAG [237]

Answer:

(a) 1.6m

(b) 6.86m

Explanation:

This is a horizontal shooting problem, so we will use the following equations.

For horizontal distance x we use:

$x(t)=x_{0}+v_{0}t$

Where $x(t)$ is the horizontal distance at a time $t$ , $x_{0}$ is the initial horizontal position which in this case will be zero: $x_{0}=0$ . And $v_{0}$ is the initial speed: $v_{0}=2m/s$

So to solve (a):

(a) At what horizontal distance from the edge is the diver 0.800 s after pushing off?

we have that the time is: $t=0.8s$ so the horizontal distance is:

$x(0.8)=(2m/s)(0.8s)1.6m$

The answer for (a) is 1.6m

Now, to solve (b) we need the equation for vertical distance:

$y(t)=y_{0}-\frac{1}{2}gt^2$

Where $y(t)$ is the vertical distance at a time $t$ , $y_{0}$ is the initial vertical distance: $y_{0}=10m$ And $g$ is the gravitational acceleration: $g=9.81m/s^2$ }

(b) At what vertical distance above the surface of the water is the diver just then?

The time is the same as in the last question: $t=0.8s$

$y(0.8)=10m-\frac{1}{2}(9.81m/s^2)(0.8)^2$

$y(0.8)=10m-\frac{1}{2}(9.81m/s^2)(0.64s^2)$

$y(0.8)=10m-\frac{1}{2}(6.2784m)$

$y(0.8)=10m-(3.1392)$

$y(0.8)=6.86m$

the answer to (b) is 6.86m

(c) At what horizontal distance from the edge does the diver strike the water?

To solve (c) we first need to know how long it took to reach the height of the water, that is, for what time y = 0

Using $y(t)=y_{0}-\frac{1}{2}gt^2$

if $y(t)=0$

$0=10-\frac{1}{2}gt^2\\-10=-\frac{1}{2}gt^2\\20=gt^2\\\frac{20}{g}=t^2\\ \sqrt{\frac{20}{g}}=t$

and since $g=9.81m/s^2$

$t=\sqrt{\frac{20}{9.81} } =\sqrt{2.039}=1.43s$

At $t=1.43s$ the car hits the water, so the horizontal distance at that time is:

$x(t)=x_{0}+v_{0}t$

$x(1.43)=(2m/s)(1.43s)=2.86m$

the answer to (c) is 2.86s

6 0

3 years ago

A chemical is always the same thing as an element . True False

olya-2409 [2.1K]

That would be false

Hope this helps :)

3 0

3 years ago

Read 2 more answers

A local fast food company sells a 16-oz soft drink. To determine if the soft drinks served contain < the advertised 16 oz, a

kakasveta [241]

Answer:

Hypothesis testing.

Explanation:

In the given problem it has been claimed that the mean of the population amount is less than 16 oz. for this claim, a test is conducted using the sample of size 20 and it was concluded that there is no evidence to say that mean amount is less than the claimed amount. i.e 16 oz

Hence, it is an example of the hypothesis testing.

6 0

3 years ago