Answer:
mass = 0.18 [kg]
Explanation:
This is a classic problem where we can apply the definition of density which is equal to mass over volume.
![density = \frac{mass}{volume} \\\\where:\\volume = 1 [m^3]\\density = 0.18[kg/m^3]](https://tex.z-dn.net/?f=density%20%3D%20%5Cfrac%7Bmass%7D%7Bvolume%7D%20%5C%5C%5C%5Cwhere%3A%5C%5Cvolume%20%3D%201%20%5Bm%5E3%5D%5C%5Cdensity%20%3D%200.18%5Bkg%2Fm%5E3%5D)
mass = 0.18*1
mass = 0.18 [kg]
Answer:
The reading will be the same.
Explanation:
Mass does not depend upon anything and it remains the same anywhere. What changes is the weight of the body because it depends upon gravity and is different at different places.
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Answer:
Final velocity will be equal to 14 m/sec
Explanation:
We have given initial velocity u = 5 m/sec
Constant acceleration is given 
Time t = 6 sec
We have to find the final velocity
From first equation of motion
, here v is final velocity, u is initial velocity , a is acceleration and t is time
So 
So equal final velocity will be equal to 14 m/sec
Answer:
Gravity: downwards
Air drag and air-pressure on the inner surface of the the parachute: Upwards
Explanation:
- If a sky-diver is in the final stages of his descend with open parachute such that the wind is calm and it does not blows him laterally.
- In such a condition the air resistance in the form of drag and the pressure force due to the air captured in the parachute are acting in the upward direction which balance the force of gravity on the body. But this situation may occur momentarily and then again the diver must begin to slowly descend.
The magnitude of the frictional force of the box is 65 N
From the question given above, the following data were obtained:
- Mass (m) = 25 Kg
- Force applied (Fₐ) = 135 N
- Net force (Fₙ) = 70 N
- Frictional force (Fբ) =?
The frictional force acting on the box can be obtained as follow:
Fₙ = Fₐ – Fբ
70 = 135 – Fբ
Collect like terms
70 – 135 = – Fբ
–65 = –Fբ
Multiply through by –1
<h3>Fբ = 65 N</h3>
Thus, the frictional force of the box is 65 N
Learn more on Frictional force: brainly.com/question/25767576