Answer:
The value is 
Explanation:
From the question we are told that
The frequency of each sound is
The speed of the sounds is 
The distance of the first source from the point considered is 
The distance of the second source from the point considered is 
Generally the phase angle made by the first sound wave at the considered point is mathematically represented as
![\phi_a = 2 \pi [\frac{a}{\lambda} + ft]](https://tex.z-dn.net/?f=%5Cphi_a%20%3D%20%202%20%5Cpi%20%5B%5Cfrac%7Ba%7D%7B%5Clambda%7D%20%20%2B%20ft%5D)
Generally the phase angle made by the first sound wave at the considered point is mathematically represented as
Here b is the distance o f the first wave from the considered point
Gnerally the phase diffencence is mathematically represented as
=> ![\Delta \phi = \frac{2\pi [ a - b]}{ \lambda }](https://tex.z-dn.net/?f=%5CDelta%20%20%5Cphi%20%20%20%3D%20%20%20%5Cfrac%7B2%5Cpi%20%5B%20a%20-%20b%5D%7D%7B%20%5Clambda%20%7D)
Gnerally the wavelength is mathematically represented as

=> 
=> 
=> ![\Delta \phi = \frac{2* 3.142 [ 4.40 - 4.0 ]}{ 0.611 }](https://tex.z-dn.net/?f=%5CDelta%20%20%5Cphi%20%20%20%3D%20%20%20%5Cfrac%7B2%2A%203.142%20%5B%204.40%20-%204.0%20%5D%7D%7B%20%200.611%20%20%7D)
=> 
Answer: Smaller than ; larger than
Explanation:
When the elevator is moving in the upward direction, then the force acting on it is negative in nature because of
N= mg +ma, (g is gravity and a is acceleration)
here ma is negative so the N= mg-ma
Hence, it feels smaller than its original weight.
When the elevator is moving downward , then the force acting will be positive in nature
N= mg+ma,
here ma will be positive so it feels larger the original weight of passenger.
Answer:
a) A1 = 
b) A1 = 2.688 cm
c) Q1 = A1 x v1
d) v1 = 3.1994 m/s
e) A2 = 
f) A2 = 0.7963cm
Explanation:
a) Area = 
r = 
thus,
area = 
A1 = ![\frac{\pi (d1)^{2} }{4}[/tex]b) d1 = 1.85 cmsubstituting in the above equation,A1 = [tex]\frac{\pi (d1)^{2} }{4}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cpi%20%28d1%29%5E%7B2%7D%20%7D%7B4%7D%5B%2Ftex%3C%2Fstrong%3E%5D%3C%2Fp%3E%3Cp%3E%3C%2Fp%3E%3Cp%3Eb%29%20d1%20%3D%201.85%20cm%3C%2Fp%3E%3Cp%3Esubstituting%20in%20the%20above%20equation%2C%3C%2Fp%3E%3Cp%3EA1%20%3D%20%20%5Btex%5D%5Cfrac%7B%5Cpi%20%28d1%29%5E%7B2%7D%20%7D%7B4%7D)
A1 = 
A1 = 2.688 cm
c) Flow rate = Area x velocity ( refer brainly.com/question/13997998)
Q1 = A1 x v1
d) From the above equation,
v1 =
=
= 319.94 cm/s = 3.1994 m/s
e) Since the flow rate Q1 is constant throughout the hose, Av is a constant.
i.e. A1 x v1 = A2 x v2
thus,
A2 = 
f) v2 = 10.8 m/s.
substituting the values in the above equation,
A2 =
= 0.7963cm
" 50 W " means " 50 Watts " or " 50 Joules per second ".
(500,002 J) / (50 J/sec) = <em>10,000.04 seconds</em>
(That's 2 hours 46 minutes 40.04 seconds.)