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jekas [21]
3 years ago
10

Phil is riding a scooter and pushes off the ground with his foot. this causes him to accelerate at 12 m /s. Phil weighs 600 N. h

ow strong was his push off the ground?​
Physics
1 answer:
Dvinal [7]3 years ago
7 0

Answer:

734.16 kg m/s^{2}

Explanation:

The problem is asking for the Force of pushing off the ground.

  • The formula of Force is: F = mass x acceleration

Given = <em>Mass</em>: 600 newtons (N)

             <em>Acceleration</em>: 12 m/s^{2}

We have to convert the mass into kg first. Remember that <u>1 kg is equal to 9.80665 newtons.</u>

Let x be the<em> mass in newtons</em>.

Let's convert: \frac{1 kg}{9.80665 N} x \frac{x}{600 N} = \frac{600}{9.80665} = 61.18 kg

Phil's weight is 61.18 kg

Let's go back to finding the force.

F = m x a

F = 61.18 kg x 12 m/s^{2}

F = 734.16 kg m/s^{2}

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<h3>What is electric potential energy?</h3>

The electric potential energy is the work done by a test charge to bring it from infinity to a particular location.

The electric potential energy is given by the relation,

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Learn more about  electric potential energy.

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Which describes how light travels?
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the Answer Would be D

Explanation:

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An electron moves at a speed of 1.0 x 104 m/s in a circular path of radius 2 cm inside a solenoid. The magnetic field of the sol
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Answer:

(a) B = 2.85 × 10^{-6} Tesla

(b) I =  I = 0.285 A

Explanation:

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⇒ B = \frac{mv}{qr}

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B = \frac{9.11*10^{-31*1.0*10^{4} } }{1.6*10^{-19}*0.02 }

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B = 2.85 × 10^{-6} Tesla

b. Given that; N/L = 25 turns per centimetre, then the current, I, can be determined by;

B = μ I N/L

⇒    I = B ÷ μN/L

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3 years ago
the wattage ratting of a light bulb is the power it sonsumers when it is connected accross a 120 V potential difference what is
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Answer:

240 Ω

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Where P = Power, V = Voltage, R = Resistance

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Given: V = 120 V, P = 60 W.

Substitute into equation 2

R = 120²/60

R = 240 Ω

Hence the resistance of the bulb = 240 Ω

8 0
3 years ago
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