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OLga [1]
3 years ago
12

Chu-Li has $100 in her piggy bank. How much will she have in her bank 40 weeks from now if she puts $1 in the bank next week, $2

two weeks from now, $3 three weeks from now, and continues to increase the amount that she puts in by $1 each week?
Mathematics
1 answer:
BigorU [14]3 years ago
6 0

Answer:

  $920

Step-by-step explanation:

The amounts added are the arithmetic sequence ...

  1, 2, 3, ... 40

The average term of this sequence is (1 +40)/2 = 20.5. The sum of the terms of this sequence is the number of terms (40) multiplied by the average term (20.5). That product is ...

  40·20.5 = 820

Chu-Li will have added $820 to her bank in 40 weeks, so the total there is ...

  $100 +820 = $920 . . . amount Chu-Li will have 40 weeks from now

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Find the missing number 29\50=__\100
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Answer:

58/100

Step-by-step explanation:

50 times 2 is 100, so we multiply the other number by 2 because what you do to the bottom you do to the top.

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6 0
3 years ago
50 ÷ 5 (5 – 3) + 5 ÷ 1/5
guapka [62]
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3 0
2 years ago
A truck traveling 45 miles per hour and a train traveling 60 miles per hour cover the same distance. The truck travels 2 hours l
anygoal [31]

Answer:

6-hours

D = C + T

Step-by-step explanation:

The following equations represent the total distance travelled by each vehicle, the truck (C) and the Train (T) where x is the amount of time travelling in hours...

C = 45x

T = 60x

Since the truck traveled 2 hours longer than the train we can add this value to the variable x in the truck's distance equation and then make both equations equal one another to calculate the number of hours before they cover the same distance...

45(x+2) = 60x  ... distribute 45 evenly

45x + 90 = 60x ... subtract 45x from both sides

90 = 15x  ... divide both sides by 15

6 = x

Finally, we can see that both vehicles would have traveled the same distance at the 6-hour mark. Now to calculate the total distance traveled (D) we can use the following equation...

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3 0
3 years ago
In 2013 your car was worth $12,500. In 2015 your car was worth $8,200.
N76 [4]

Answer:

A) V =12500[1-\frac{17.2 \times t}{100} ]

B)  V = 12500[1-\frac{19}{100} ]^{t}

Step-by-step explanation:

In two years i.e. from 2013 to 2015 the car value decreases from $12500 to $8200.

a) If the rate of decrease is constant and it is r% per year, then

8200 = 12500[1-\frac{r \times 2}{100}}]

⇒ r = 17.2%

Therefore, the value of the car is given by V =12500[1-\frac{17.2 \times t}{100} ], where, t is in years since 2013. (Answer)

b) If the rate of decrease is exponential and it is r%, then

8200 = 12500[1-\frac{r}{100} ]^{2}

⇒ r = 19%

Therefore, the value of the car is given by V = 12500[1-\frac{19}{100} ]^{t}, where, t is in years since 2013. (Answer)

3 0
3 years ago
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