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zavuch27 [327]
3 years ago
8

You have to write 0.33 as a fraction.how do you choose the denominator?

Mathematics
2 answers:
yaroslaw [1]3 years ago
8 0
100 is the easiest because 1/100 =0.01
33/100=0.33
Arlecino [84]3 years ago
3 0
Just put your decimal over 100, and that's it.

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The graph represents f(x), and g(x) = 7x – 42.
Aliun [14]
g(x)=7x-42\\\\\y-intercept\ of\ g(x):\\\\f(0)=7\cdot0-42=-42\to(0;\ -42)\\\\x-intercept\ of\ g(x):\\\\0=7x-42\ \ \ \ |+42\\7x=42\ \ \ |:7\\x=6\to(6;\ 0)

f(x)=ax+b\\\\y-intercept\ of\ f(x):\ (0;\ -3)\\\\x-intercept\ of\ f(x):\ (6;\ 0)

Answer:

A) the y-intercept of g(x) is less than the y-intercept of f(x).


4 0
4 years ago
PLS HELP WILL GIVE BRAINLIEST
NNADVOKAT [17]
I think it would be 30? I’m not sure about that one.. sorry
3 0
3 years ago
PLEASE HELP QWQ AsAp with these 4 questions
den301095 [7]

Answer:

Step-by-step explanation:

I can't believe I'm doing this for 5 points, but ok!

For the first 3, we are going to multiply to find the value of that 3 x 3 matrix by picking up the first 2 columns and plopping them down at the end and then multiplying through using the rules for multiplying matrices:

\left[\begin{array}{ccccc}7&4&6&7&4\\-4&8&9&-4&8\\1&8&7&1&8\end{array}\right]  and from there find the sum of the products of the main axes minus the sum of the products of the minor axes, as follows (I'm not going to state the process in the next 2 problems, so make sure you follow it here. This is called the determinate. The determinate is what you get when you evaluate or find the value of a matrix. Just so you know):

(7*8*7)+(4*9*1)+(6*-4*8)-[(1*8*6)+(8*9*7)+(7*-4*4)] which gives us:

392 + 36 - 192 - [48 + 504 - 112] which simplifies to

236 - 440 which is -204

On to the second one:

\left[\begin{array}{ccccc}-8&-4&-1&-8&-4\\1&7&-3&1&7\\8&9&9&8&9\end{array}\right] and multiplying gives us

(-8*7*9)+(-4*-3*8)+(-1*1*9)-[(8*7*-1)+(9*-3*-8)+(9*1*-4)] which gives us:

-504 + 96 - 9 - [-56 + 216 - 36] which simplifies to

-417 - 124 which is -541, choice c.

Now for the third one:

\left[\begin{array}{ccccc}-2&-2&-5&-2&-2\\2&7&-3&2&7\\8&9&9&8&9\end{array}\right] and multiplying gives us

(-2*7*9)+(-2*-3*8)+(-5*2*9)-[(8*7*-5)+(9*-3*-2)+(9*2*-2)] which gives us:

-126+48-90-[-280+54-36] which simplifies to

-168 - (-262) which is 94, choice c again.

Now for the last one. I'll show you the set up for the matrix equation; I solved it using the inverse matrix. So I'll also show you the inverse and how I found it.

\left[\begin{array}{cc}-4&-5&\\-6&-8\\\end{array}\right] \left[\begin{array}{c}x\\y\\\end{array}\right] = \left[\begin{array}{c}-5\\-2\\\end{array}\right] and I found the inverse of the 2 x 2 matrix on the left.

Find the inverse by:

* finding the determinate

* putting the determinate under a 1

* multiply that by the "mixed up matrix (you'll see...)

First things first, the determinate:

|A| = (-4*-8) - (-6*-5) which simplifies to

|A| = 32 - 30 so

|A| = 2; now put that under a 1 and multiply it by the mixed up matrix. The mixed up matrix is shown in the next step:

\frac{1}{2}\left[\begin{array}{cc}-8&5\\6&-4\end{array}\right]  (to get the mixed up matrix, swap the positions of the numbers on the main axis and then change the signs of the numbers on the minor axis). Now we multiply in the 1/2 to get the inverse:

\left[\begin{array}{cc}-4&\frac{5}{2}\\3&-2\\\end{array}\right] Multiply that inverse by both sides of the equation. This inverse "undoes" the matrix that's already there (like dividing the matrix that's already there by itself) which leaves us with just the matrix of x and y. Multiply the inverse matrix by the solution matrix:

\left[\begin{array}{c}x&y\end{array}\right] =\left[\begin{array}{cc}-4&\frac{5}{2} \\3&-2\end{array}\right] *\left[\begin{array}{c}-5&-2\\\end{array}\right] and that right side multiplies out to

x = 20 - 5 which is

x = 15 and

y = -15 + 4 which is

y = -11

(It works, I checked it)

7 0
3 years ago
Side1 : 3x^2 − 4x − 1 (^to the second power)
Colt1911 [192]

9514 1404 393

Answer:

  A. 2x^2 +4

  B. 5x^3 -4x^2 +3x -12

  C. addition and subtraction of polynomials result in polynomials (closed)

Step-by-step explanation:

A. The total of the two side lengths is ...

  (3x^2 -4x -1) +(-x^2 +4x +5) = (3 -1)x^2 +(-4+4)x +(-1+5) = 2x^2 +4

__

B. The length of the third side is the difference between the total for all three sides and the total for the given two sides:

  (5x^3 -2x^2 +3x -8) - (2x^2 +4) = 5x^3 +(-2-2)x^2 +3x +(-8-4)

  = 5x^3 -4x^2 +3x -12

__

C. Addition of the two polynomials results in a polynomial. Subtraction of the two polynomials results in a polynomial. There is nothing here to indicate the set of polynomials is not closed under addition and subtraction.

7 0
3 years ago
Whose class would you rather be in, if each teacher has different grading schemes?
Darina [25.2K]

Answer:

Mr. Winking 87.9%

Ms. Sand 88.55%

Ms. Sand's class is better

Step-by-step explanation:

Step 1: Average in Mr. Winking's Class 87.9%

Convert each weight factor to a decimal.

Homework 10% = 0.1

Quiz 25% = 0.25

Test 45% = 0.45

Exam 20% = 0.2

Multiply your grades by the weight factors:

Homework 0.1 X 95% = 9.5%

Quiz 0.25 X 85% = 21.25%

Test 0.45 X 87% = 39.15%

Exam 0.2 X 90% = 18%

Add all of these values:

9.5% + 21.25% + 39.15% + 18%

= 87.9%

Step 2: Average in Ms. Sand’s Class 88.55%

Convert each weight factor to a decimal.

Homework 15% = 0.15

Quiz 20% = 0.2

Test 40% = 0.4

Exam 25% = 0.25

Multiply the weight factors by your grades:

Homework 0.15 X 95% = 14.25

Quiz 0.2 X 85% = 17

Test 0.4 X 87% = 34.8

Exam 0.25 X 90% = 22.5

All all these values:

14.25 + 17 + 34.8 + 22.5

= 88.55%

Step 3:

I would rather be in Ms. Sand's class. My average in her class would be 88.55%, whereas in Mr.Winking's Class, my average would be 87.9%. 88.55% is a higher mark than 87.9% and I want higher marks. Therefore, I would get higher marks in Ms. Sand's class.

6 0
4 years ago
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