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Question #32:</h3>
Solve: 4/m - 8 = 8/2
Cross Multiply: 4 * 2 = 8 * (m - 8)
Simplify: 8 = 8m - 64
Flip the Equation: 8m - 64 = 8
Add 64 to both sides: 8m + (-64) + 64 = 8 + 64
Simplify: 8m = 72
Divide both sides by 8: 8m/8 = 72/8
Final Answer: m = 9
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<h3>
Question #33:</h3>
Solve: 7/b + 5 = 10/5
Cross Multiply: 7 * 5 = 10 * (b + 5)
Simplify: 35 = 10b + 50
Flip the Equation: 10b + 50 = 35
Subtract 50 to both sides: 10b + 50 - 50 = 35 - 50
Simplify: 10b = -15
Divide both sides by 10: 10b/10 = -15/10
Final Answer: b = -3/2
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Hope This Helped! Good Luck!
In geometry, there is a theorem that states: The sum of any two sides of a triangle is greater than that of the third
Let's try to plug in and find if any two sides added together will be greater than the third:
a) 2 cm
3+5=8 and 8>2 [acceptable]
2+3=5 but 5=5 [not acceptable]
2+8=10 and 10>5 [acceptable]
b) 3 cm
3+3=6, 6>5 [good]
3+5=8, 8>3 [good]
.....
etc
We found that the answer has to be 2cm, because if we were to add a side of 2cm with 3cm, it would equal to the third side and the theorem states that the sum has to be greater
Hope this helped :) If so, leave a rating :)
I'll do this step-by-step. Note, ratios are basically division signs.
The ratio of cars to motorcycles in a parking lot is 10:3, which means there are 10 cars for every 3 motorcycles.
The ratio of motorcycles to vans is 2:3, there are 2 motorcycles for every 3 vans.
There are 30 vans, so there are 20 motorcycles, since 20 motorcycles:30 vans is equal to 2 motorcycles: 3 vans in fractions. (20 / 30 = 2 / 3)
So, the ratio of cars represented by x to the number of motorcycles, 20 can be written as x / 20 = 10 / 3. 10 / 3 is 3.333, meaning 3.333 cars per 1 motorcycle, so multiply 20 by 3.333 to get x, which is 66. There are 66 cars and 30 vans, so there are 33 more cars than vans in the parking lot. 66/20 = 10/3, both have a ratio of 3.33 when divided.
If you don't want the explanation, there are 33 more cars than vans in the parking lot.
100*x I think I’m sorry that’s a poor answer I have done this in years
