Answer: v = Fo(1-T)/m
Step-by-step explanation: shown in the attachment
Answer:
there is something missing in your question.
Step-by-step explanation:
<span>Minute hand 9mm
Hour Hand 5mm
c2 = a2 + b2 - 2abcosC
c2 = 92 +52 - 2 * 9 *5 cosC
c2 = 96 - 90 cosC
2c dc/dt = 90 sinC dC/dt
at one o'clock:
C = 30 degrees=> sin(30) = 1/2
dC/dt = 2pi - pi/6 = 11pi/6 => -11pi/6
c2= 96 - 90 cos (30)
c = âš(96 -45âš3)
2 dc/dt = 90 * 1/2 * -11pi/6
dc/dt = -25 mm/h
hence the distance between hands is decreasing at 25 mm/hr</span>
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