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vampirchik [111]
3 years ago
5

Simplify. Rationalize the denominator. -3/5 + √3

Mathematics
1 answer:
Dahasolnce [82]3 years ago
3 0

Answer: -3-5\sqrt{3} / 5

Step-by-step explanation

To write \sqrt{3} as a fraction with a common denominator, multiply by 5/5.

-3/5 + \sqrt{3} * 5/5

Then combine fractions, so that the numeratiors over the common denominator.  

-3 + 5 \sqrt{3} /5

Simplify with factoring out.

Rewrite -3 as -1 (3). Next factor -1 out of 5 \sqrt{3}. Then facotr -1 out of -1(3) - (-5\sqrt{3}). After that move teh negative in front of the fraction.

Exact Form: - 3-5\sqrt{3} / 5

Decimal Form: 1.13

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Kitty [74]

Answer:

maximum: y = 1

minimum: y = 0.

Step-by-step explanation:

Here we have the function:

y = f(x) =  √(1 + x^2 - 2x)

we want to find the minimum and maximum in the segment [0, 1]

First, we evaluate in the endpoints, which are 0 and 1.

f(0)  =√(1 + 0^2 - 2*0) = 1

f(1) = √(1 + 1^2 - 2*1) = 0

Now let's look at the critical points (the zeros of the first derivate)

To derivate our function, we can use the chain rule:

f(x) = h(g(x))

then

f'(x) = h'(g(x))*g(x)

Here we can define:

h(x) = √x

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Then:

f(x) = h(g(x))

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this function does not have any zero in the segment [0, 1] (you can look it in the image below)

Thus, the function does not have critical points in the segment.

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