PQ is the tangent, therefore you can use a theorem: The arc measure is double the amount of the angle the tangent makes.
So: 62/2=31
Answer:
a=1
b= 1/16
c= 1/256
d= 1
e= 4/9
f= 16/81
Step-by-step explanation:
Plug in the values of X on the left side of the table into the function on the right side of the table. Remember that negative exponents mean the number is under a fraction. 4^-0 is like saying one over 4^0.
For the blue table, because the numbers are already in a fraction and in parentheses, you apply the exponent to each number individually.
Answer:
x = 6
Step-by-step explanation:
Basically 16x + 14 = 180 - 70 because equal angles are subtended by the transversal for two parallel lines.
So, 16x = 96 and x = 6.
<u><em>MARK AS BRAINLIEST.</em></u>
An isosceles triangle is a type of triangle where 2 sides are equal.
Picture out 2 triangles with the same base length.
On the first triangle, its legs are twice the length of the legs of the second triangle.
To put it into variables, let:
B = the same base length of the two triangles
A = the length of one leg the smaller triangle
2A = the length of one leg of the bigger triangle
Given: Perimeter of smaller triangle = 23cm
Perimeter of bigger triangle = 43cm
Recall the formula for solving the perimeter of a triangle:
Perimeter = A + B + C
where, A, B, and C are the legs of the triangle
Since the triangle involved is an isosceles triangle, therefore, we can say that
Perimeter = 2A + B , 2 legs are equal ( A=C )
Substituting the given perimeter value to the formula.
23cm = 2A + B ⇒ equation 1 (smaller triangle)
43cm = 2(2A) + B ⇒ equation 2 (bigger triangle)
Simplifying equation 2.
43cm = 4A + B
(rearranging) B = 43cm - 4A ⇒ equation 3
Substituting equation 3 to equation 1:
(equation 1) 23cm = 2A + B
23cm = 2A + (43cm - 4A)
23cm = -2A + 43cm
2A = 43cm - 23cm
2A = 20cm ⇒ length of the leg of the bigger triangle
A = 10cm ⇒ length of the leg of the smaller triangle
To solve for the base length, just substitute the value of A to equation 3
(equation 3) B = 43cm - 4A
B = 43cm - 4(10cm)
B = 3 cm
Final Answer:
• For the smaller triangle, the length of the sides are 10cm, 10cm, and 3cm
• For the bigger triangle, the length of the sides are 20cm, 20cm, and 3cm
Answer:
(√2)/2
Step-by-step explanation:
The ratio of the radius of the circle to the side of the inscribed square is the same regardless of the size of the objects.
The radius of the circle is half the length of the diagonal of the square. For simplicity, we can call the side of the square 1, so its diagonal is √(1²+1²) = √2 by the Pythagorean theorem. The radius is half that value, so is (√2)/2. The desired ratio is this value divided by 1.
Scaling up our unit square to one with a side length of 3 inches, we have ...
radius/side = ((3√2)/2) / 3 = (√2)/2
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A square with a side length of 3 inches will have an area of (3 in)² = 9 in².
