Question

Rearranging literal equations!! really confused ASAPplease

Answer 1

Answer:

b = $\frac{8a-55}{5-a}$

Step-by-step explanation:

To clear the radicals square both sides

$\frac{1}{6-a}$ = $\frac{8+b}{b-7}$ ( cross- multiply )

(6 - a)(8 + b) = b - 7 ← expand factors on left using FOIL

48 + 6b - 8a - ab = b - 7 ( subtract 48 from both sides )

6b - 8a - ab = b - 55 ( add 8a to both sides )

6b - ab = b - 55 + 8a ( subtract b from both sides )

6b - ab - b = 8a - 55, that is

5b - ab = 8a - 55 ← factor out b from each term on the left side )

b(5 - a) = 8a - 55 ← divide both sides by (5 - a)

b = $\frac{8a-55}{5-a}$