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koban [17]
3 years ago
13

The molar volume of gas at STP, in liters, is?

Chemistry
1 answer:
defon3 years ago
7 0
<span>The molar volume of a gas at STP, in liters, is 22.4

you then multiply 22.4 by 2 to get the answer to the next question:
</span><span>
You can use the molar volume to convert 2 mol of any gas to 44.8 L
</span>
<span>You can also use the molar volume to convert 11.2 L of any gas to 0.500 mol.
</span>
Avogadro’s law tells you that 1.2 L of O2(g) and 1.2 L of NO2(g<span>) are the same </span><span>numbers of moles of gas.</span>

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CaCl2<br> Ca +<br> CI2<br> Balance this equation
Elis [28]

To balance Ca + Cl2 = CaCl2 you'll need to be sure to count all of atoms on each side of the chemical equation.

Once you know how many of each type of atom you can only change the coefficients (the numbers in front of atoms or compounds) to balance the equation for Calcium + Chlorine gas.

3 0
3 years ago
If 27.0 mL of Ca(OH)2 with an unknown concentration is neutralized by 32.40 mL of 0.185 M HCl, what is the concentration of the
zhannawk [14.2K]

Given information : Volume of HCl = 32.40 mL

32.40 mL\times \frac{1 L}{1000 mL}

Volume of HCl = 0.0324 L

Concentration of HCl = 0.185 M or 0.185 mol/L (M = mol/L)

Volume of Ca(OH)2 = 27.0 mL

27.0 mL\times \frac{1 L}{1000 mL}

Volume of Ca(OH)2 = 0.027 L

We need to find the concentration of Ca(OH)2.

To find the concentration of Ca(OH)2 we need moles and volume of Ca(OH)2.

Concentration (Molarity) = \frac{(Moles of Ca(OH)2)}{(Volume of Ca(OH)2)}

Moles of Ca(OH)2 can be calculated using stoichiometry and volume of Ca(OH)2 is already given to us.

Step 1 : Find the moles of HCl using its given volume and concentration.

Moles = Concentration \times Volume in L

Moles = 0.185\frac{mol}{1L}\times 0.0324 L

Moles of HCl = 0.005994 mol HCl

Step 2 : We need to find moles of Ca(OH)2 using mol of HCl with the help of mole ratio.

Mole ratio are the coefficient present in front of the compound in a balanced equation.

Mole ratio of Ca(OH)2 : HCl = 1:2 ( 1 coefficient of Ca(OH)2 and 2 coefficient of HCl)

(0.005994 mol HCl)\times \frac{(1 mol Ca(OH)2)}{(2 mol HCl)}

Moles of Ca(OH)2 = 0.002997 mol Ca(OH)2

Step 3 : Find the concentration of Ca(OH)2 using its moles and volume.

Concentration (Molarity) = \frac{(Moles of Ca(OH)2)}{(Volume of Ca(OH)2)}

Moles of Ca(OH)2 = 0.002997 mol and volume of Ca(OH)2 = 0.027 L

Concentration (Molarity) = \frac{(0.002997 mol)}{(0.027 L)}

Concentration of Ca(OH)2 = 0.111 mol/L or 0.111 M


4 0
4 years ago
a compound containing only carbon and hydrogen produces 1.80 gCO2 and 0.738 gH2O. Find the empirical formula of the compound. Ex
r-ruslan [8.4K]

Answer:

The empirical formula is CH2

Explanation:

Step 1: Data given

Mass of CO2 produced = 1.80 grams

Mass of H2O produced = 0.738 grams

Step 2: The balanced equation

CxHy + O2 → CO2 + H2O

Step 3: Calculate moles CO2

Moles CO2 = mass CO2 / molar mass CO2

Moles CO2 = 1.80 grams / 44.01 g/mol

Moles CO2 = 0.0409 moles

Step 4: Calculate moles C

In 1 mol CO2 we have 1 mol CO2

In 0.0409 moles CO2 we have 0.0409 mol C

Step 5: Calculate moles H2O

Moles H2O = mass H2O / molar mass H2O

Moles H2O = 0.738 grams / 18.02 g/mol

Moles H2O = 0.04095  moles

Step 6: Calculate moles H

In 1 mol H2O we have 2 moles H

In 0.04095 moles H2O we have 2*0.04095 = 0.0819 moles H

Step 7: Calculate the mol ratio

We divide by the smallest amount of moles

C: 0.0409 / 0.0409 = 1

H: 0.0819 moles / 0.0409 =  2

The empirical formula is CH2

4 0
3 years ago
4. Some characteristic types of wind result where global pressure belts meet. Which of the following is a zone of weak, variable
PIT_PIT [208]

Answer:

local winds

Explanation:

4 0
3 years ago
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jamie is not sure a new medication will work because it has not had a large test group. Is jamie being creative?
Georgia [21]

Answer:

yes because I wouldn't do it

7 0
3 years ago
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