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alekssr [168]
3 years ago
10

What mass of C6H12O6 is needed to make a 0.1 liter solution with a concentration of 0.1 moles?

Chemistry
1 answer:
Alenkinab [10]3 years ago
6 0

Answer:

18g of C6H12O6 is required

Explanation:

The molar mass of C6H12O6 is 180g/mol

But no of mole = mass/ molar mass

0.1 = reacting mass / 180

Reacting mass = 0.1 × 180

= 18g

i.e 18g of C6H12O6 will react to yield 0.1 moles of C6H12O6....

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Answer:

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How many formula units are contained in 0.57 g Cao?
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Then you will multiply the number of moles by 6.022×1023formula units/mol . To determine the molar mass of a compound, add the atomic weight on the periodic table in g/mol times each element's subscript. Since the formula unit CaO has no subscripts, they are understood to be 1
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Anyone know why its important for membranes to be selectivity permeable?
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The term, selectively permeable, refers to the fact that the membrane allows some substances or molecules to enter the cells, and others to be prevented from entering. It also allows substances to leave the cell. All of this is dependent on the size of the molecule and the concentrations on either side of the membrane.

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Concept map of MATTER - can be a substance- can be a
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3 0
3 years ago
A 0.67 gram sample of chromium is reacted with sulfur. The resulting chromium sulfide has a mass of 1.2888 grams. What is the em
spin [16.1K]

Answer:

Cr₂S₃

Explanation:

From the question given above, the following data were obtained:

Mass of chromium (Cr) = 0.67 g

Mass of chromium sulfide = 1.2888 g

Empirical formula =?

Next, we shall determine the mass of sulphur (S) in the compound. This can be obtained as follow:

Mass of chromium (Cr) = 0.67 g

Mass of chromium sulfide = 1.2888 g

Mass of sulphur (S) =?

Mass of S = (Mass of chromium sulfide) – (Mass of Cr)

Mass of S = 1.2888 – 0.67

Mass of S = 0.6188 g

Finally, we shall determine the empirical formula of the compound. This can be obtained as follow:

Mass of Cr = 0.67 g

Mass of S = 0.6188 g

Divide by their molar mass

Cr = 0.67 / 52 = 0.013

S = 0.6188 / 32 = 0.019

Divide by the smallest

Cr = 0.013 / 0.013 = 1

S = 0.019 / 0.013 = 1.46

Multiply by 2 to express in whole number

Cr = 1 × 2 = 2

S = 1.46 × 2 = 3

Therefore, the empirical formula of the compound is Cr₂S₃

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