Then you will multiply the number of moles by 6.022×1023formula units/mol . To determine the molar mass of a compound, add the atomic weight on the periodic table in g/mol times each element's subscript. Since the formula unit CaO has no subscripts, they are understood to be 1
The term, selectively permeable, refers to the fact that the membrane allows some substances or molecules to enter the cells, and others to be prevented from entering. It also allows substances to leave the cell. All of this is dependent on the size of the molecule and the concentrations on either side of the membrane.
Selectively permeable membranes are important in maintaining homeostasis, fluid and electrolyte balance, and cellular health. Cells need to receive glucose and other nutrients in order to carry on normal cellular processes, and eliminate waste products of metabolism to avoid the accumulation of cellular toxins which can disrupt cellular processes and lead to cellular death.
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Substance - Elements and Compounds
Example of element is oxygen and that of compound is water.
Matter can be classified into mixture.
It can be heterogeneous and homogenous.
Example of heterogeneous mixture is milk.
Example of homogeneous mixture is air.
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Answer:
Cr₂S₃
Explanation:
From the question given above, the following data were obtained:
Mass of chromium (Cr) = 0.67 g
Mass of chromium sulfide = 1.2888 g
Empirical formula =?
Next, we shall determine the mass of sulphur (S) in the compound. This can be obtained as follow:
Mass of chromium (Cr) = 0.67 g
Mass of chromium sulfide = 1.2888 g
Mass of sulphur (S) =?
Mass of S = (Mass of chromium sulfide) – (Mass of Cr)
Mass of S = 1.2888 – 0.67
Mass of S = 0.6188 g
Finally, we shall determine the empirical formula of the compound. This can be obtained as follow:
Mass of Cr = 0.67 g
Mass of S = 0.6188 g
Divide by their molar mass
Cr = 0.67 / 52 = 0.013
S = 0.6188 / 32 = 0.019
Divide by the smallest
Cr = 0.013 / 0.013 = 1
S = 0.019 / 0.013 = 1.46
Multiply by 2 to express in whole number
Cr = 1 × 2 = 2
S = 1.46 × 2 = 3
Therefore, the empirical formula of the compound is Cr₂S₃
