What is the word equation of photodecomposition?

Chemistry

1 answer:

Oksi-84 [34.3K]2 years ago

7 0

Answer:

I have for Decompostion

Explanation:

A decomposition reaction occurs when one reactant breaks down into two or more products. It can be represented by the general equation: AB → A + B. In this equation, AB represents the reactant that begins the reaction, and A and B represent the products of the reaction

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What is the mass in grams of 9.76 x 10 12 atoms of naturally occurring sodium?

Fiesta28 [93]

The number of moles in a substance indicates the amount of the substance that contains the same number of particles as 12 g of the Carbon-12 isotope [or equivalent to 6.02 × 10²³] (which is used as a standard in the world of moles).

Now,

if 6.02 × 10²³ atoms are found in 1 mole ofsodium
then let 9.76 × 10¹² atoms are found in x

⇒ x = (9.76 × 10¹² ) ÷ (6.02 × 10²³)

= 1.619 × 10⁻¹¹ mol

Now, mass = moles × molar mass

∴ mass of Na = 1.619 × 10⁻¹¹ mol × 23 g/mol
= 3.72 × 10⁻¹⁰ g

4 0

3 years ago

Aluminum chloride, AlCl3, is an inexpensive reagent used in many industrial processes. It is made by treating scrap aluminum wit

mylen [45]

Answer:

83.8%

Explanation:

The balanced reaction equation is;

2Al(s) + 3Cl2(g) → 2AlCl3(s)

Now we have to obtain the limiting reactant as the reactant that produces the least amount of AlCl3

Amount of Al = 3.11g/27 g/mol = 0.115 moles

If 2 moles of Al yields 2 moles of AlCl3

Then 0.115 moles of Al yields 0.115 moles of AlCl3

For Cl2

Amount of Cl2 = 5.32 g/71 g/mol= 0.075 moles

If 3 moles of Cl2 yields 2 moles of AlCl3

0.075 moles of Cl2 yields 0.075 * 2/3 = 0.05 moles of AlCl3

Hence Cl2 is the limiting reactant

Theoretical yield of AlCl3 = 0.05 moles of AlCl3 * 133g/mol = 6.65 g

%yield = actual yield /theoretical yield * 100

%yield = 5.57 g/6.65 g * 100

%yield = 83.8%

4 0

2 years ago

How many grams of h2 will be produced if 175g of HCI are allowed to react completely with sodium

Sedbober [7]

Answer:

4.8 grams of H₂ will be produced if 175g of HCI are allowed to react completely with sodium

Explanation:

By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction) you can see that the following amounts in moles of each compound react and are produced:

HCl: 2 moles
Na: 1 mole
NaCl: 2 moles
H₂: 1 mole

You know the following masses of each element:

H: 1 g/mole
Cl: 35.45 g/mole
Na: 23 g/mole

So, the molar mass of each compound participating in the reaction is:

HCl: 1 g/mole + 35.45 g/mole= 36.45 g/mole
Na: 23 g/mole
NaCl: 23 g/mole + 35.45 g/mole= 58.45 g/mole
H₂: 2* 1 g/mole= 2 g/mole

Then, by stoichiometry of the reaction, the following amounts in grams of each of the compounds participating in the reaction react and are produced:

HCl: 2 moles* 36.45 g/mole= 72.9 g
Na: 1 mole* 23 g/mole= 23 g
NaCl: 2 moles* 58.45 g/mole= 116.9 g
H₂: 1 mole* 2 g/mole= 2 g

So, a rule of three applies as follows: if by stoichiometry, when reacting 72.9 grams of HCl 2 grams of H₂ are formed, when reacting 175 grams of HCl how much mass of H₂ will be formed?

$mass of H_{2} =\frac{175 g of HCl*2g ofH_{2} }{72.9 g of HCl}$