Answer : The volume of 3.0 M spinach solution added should be, 50 mL
Explanation :
Formula used :
where,
are the initial molarity and volume of spinach solution.
are the final molarity and volume of diluted spinach solution.
We are given:
Now put all the given values in above equation, we get:
Hence, the volume of 3.0 M spinach solution added should be, 50 mL
Answer:
Acid + Oxide or Hydroxide
Many oxide, hydroxide and carbonate compounds
are insoluble in water, but do react with acid.
Acid + Oxide → Salt + Water
Acid + Hydroxide → Salt + Water
MgO (s) + HNO3 (aq) → Mg(NO3)2 (aq) + H2O (l)
CuOH (s) + HCl (aq) → CuCl (aq) + H2O (l)
Explanation:
lead compounds are the oxides: lead monoxide, PbO, in which lead is in the +2 state; lead dioxide, PbO2, in which lead is in the +4 state; and trilead tetroxide, Pb3O4. Lead monoxide exists in two modifications, litharge and massicot. Litharge, or alpha lead monoxide, is a red or reddish…
Enzymes catalyze the chemical reactions, they act upon the reaction substrates and speed up the reaction. Enzymes have active sites, the places where the reaction substrates interact with the enzyme bringing about the conversion of substrates to products. So, as the enzyme concentration increases the rate of reaction increases till a point where the rate is leveled off. The rate does not further increase, as the substrate might have become limiting at that point. All the available amount of substrate would have been associated with the active sites of the enzymes. So, at that point although there is enough catalyst, lack of substrate would limit the rate of reaction.
Answer:
100 degree celcius, because it is the melting point of ice ob
Answer:
Mass = 18.9 g
Explanation:
Given data:
Mass of Al₂O₃ formed = ?
Mass of Al = 10.0 g
Solution:
Chemical equation:
4Al + 3O₂ → 2Al₂O₃
Number of moles of Al:
Number of moles = mass/molar mass
Number of moles = 10.0 g/ 27 g/mol
Number of moles = 0.37 mol
Now we will compare the moles of Al and Al₂O₃.
Al : Al₂O₃
4 : 2
0.37 : 2/4×0.37 = 0.185 mol
Mass of Al₂O₃:
Mass = number of moles × molar mass
Mass = 0.185 mol × 101.9 g/mol
Mass = 18.9 g
