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3 years ago

Which statement correctly describes the click on the letter to your answer only

Mathematics

2 answers:

julsineya [31]3 years ago

5 0

Answer:

i would say either a or c

Step-by-step explanation:

Mice21 [21]3 years ago

3 0

Answer:

I say a

Step-by-step explanation:

You might be interested in

Expand the linear expression below <br> -5(-3 x -6)

Annette [7]

Answer:

15 x 30

Step-by-step explanation:

Distribute -5 to each variable in the parenthesis.

-5 x -3 = 15

-5 x -6 = 30

15 x 30

8 0

2 years ago

Explain why the following statement IS NOT a statistical question. "How

deff fn [24]

Answer:

Because it only has one answer and there are no variety of answers.

hope this helps

7 0

2 years ago

What is the distance between the points (-3,5) and (3,-8) in the standard (x,y) coordinate plane?

zlopas [31]

The vertical distance is 5 + 8 = 13
the horizantal distance is 3 +3 = 6
then just do pythag therom
6^2 + 13^2 = c^2
205 = c^2
<span>√205 = c
</span>

6 0

3 years ago

Read 2 more answers

G=[(4,-6), (-9.0), (-9,-4), (-8,4)] what is the domain and range of G?

s2008m [1.1K]

Hey there!
The domain and range for G are as follows:
Domain: -9, -9, -8, 4
Range: -6, -4, 0, 4
Hope this answer helps you out!

4 0

3 years ago

[Q71 Suppose that the height, in inches, of a 25-year-old man is a normal random variable with parameters g = 71 inch and 02 = 6

viktelen [127]

Answer: (a) Percentage of 25 year old men that are above 6 feet 2 inches is 11.5%.

(b) Percentage of 25 year old men in the 6 footer club that are above 6 feet 5 inches are 2.4%.

Step-by-step explanation:

Given that,

Height (in inches) of a 25 year old man is a normal random variable with mean $g=71$ and variance $o^{2} =6.25$ .

To find: (a) What percentage of 25 year old men are 6 feet, 2 inches tall

(b) What percentage of 25 year old men in the 6 footer club are over 6 feet. 5 inches.

Now,

(a) To calculate the percentage of men, we have to calculate the probability

P[Height of a 25 year old man is over 6 feet 2 inches]= P[X> $74in$ ]

P[X>74] = P[ $\frac{X-g}{o}$ > $\frac{74-71}{2.5}$ ]

= P[Z > 1.2]

= 1 - P[Z ≤ 1.2]

= 1 - Ф (1.2)

= 1 - 0.8849

= 0.1151

Thus, percentage of 25 year old men that are above 6 feet 2 inches is 11.5%.

(b) P[Height of 25 year old man is above 6 feet 5 inches gives that he is above 6 feet] = P[X, $6ft$ $5in$ - X, $6ft$ ]

P[X > $6ft$ $5in$ I X > $6ft$ ] = P[X > 77 I X > 72]

= $\frac{P[X > 77]}{P[ X > 72]}$

= $\frac{P[\frac{X - g}{o}>\frac{77-71}{2.5}] }{P[\frac{X-g}{o} >\frac{72-71}{2.5}] }$

= $\frac{P[Z >2.4]}{P[Z>0.4]}$

= $\frac{1-P[Z\leq2.4] }{1-P[Z\leq0.4] }$

= $\frac{1-0.9918}{1-0.6554}$

= $\frac{0.0082}{0.3446}$

= 0.024

Thus, Percentage of 25 year old men in the 6 footer club that are above 6 feet 5 inches are 2.4%.

4 0

3 years ago