See how many 5s there are in 47? There are 9 and also a leftover 2 which is your remainder.<span />
Answer:
40%
Step-by-step explanation:
x = # of values below x/n * 100
14 = 4/10 * 100
14 = 40
Answer:
A(1)=4
A(n)= A(n-1)-5
Step-by-step explanation:
Plug in 1 to see that a(1)=4. Then, find a few more using the given formula and see what the change is from one to the next. It ends up subtracting 5 for every value.
So 7 x = x2 -18 so you get the quadratic x^2 -7x -18 and then get 2 x -9= -18 and 2 + -9 = -7 so you get (x + 2) ( x - 9) so the positive solution would be x-9 = 0 so x= 9. Hope this helps :)
Answer: 29.28 years
Explanation:
From Kepler's third law the square of orbital period of revolving celestial body is proportional to the cube of semi -major axis from the body it is revolving about.
P² =A³
Where, P is the orbital period in years and A is the semi-major axis in AU (Astronomical units)
It is given that, For Saturn, A = 9.5 AU. We need to find P
⇒P² = (9.5 AU)³
⇒P² = 857.38
⇒P = 29.28 years
Thus, the orbital period of Jupiter is 29.28 years around the Sun.
