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algol [13]
3 years ago
11

Find the distance between the point (3,1) and the line with the equation y=2x-5

Mathematics
1 answer:
True [87]3 years ago
3 0

Answer:

B:  0

Step-by-step explanation:

Note that (3, 1) satisfies the equation y = 2x - 5:

1 = 2(3) - 5

1  =  6 -5  = 1

Therefore, the distance between this point and this line is zero.

B is the correct answer.

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The mean of a set of numbers is 8, and the mode is 9.
ryzh [129]
You can start by looking at the mode of the set of number automatically b and d are eliminated. We then proceed to calculate the mean so add all the numbers in A so it’ll be, 52 then divide by the amount of numbers in the set so 6. 52/6 =8.6
And C ends up being 48 so 48/6 = 8
Therefore your answer is C
5 0
3 years ago
Plz Help!! With 5,6,7,8
strojnjashka [21]

6 is 9.088 because it said it for u

8 0
3 years ago
Given: BD bisects ABC. Auxiliary EA is drawn such that AE || BD. Auxiliary BE is an extension of BC
AnnZ [28]
The required proof is given in the table below:

\begin{tabular}{|p{4cm}|p{6cm}|} 
 Statement & Reason \\ [1ex] 
1. $\overline{BD}$ bisects $\angle ABC$ & 1. Given \\
2. \angle DBC\cong\angle ABD & 2. De(finition of angle bisector \\ 
3. $\overline{AE}$||$\overline{BD}$ & 3. Given \\ 
4. \angle AEB\cong\angle DBC & 4. Corresponding angles \\
5. \angle AEB\cong\angle ABD & 5. Transitive property of equality \\ 
6. \angle ABD\cong\angle BAE & 6. Alternate angles
\end{tabular}
\begin{tabular}{|p{4cm}|p{6cm}|}
7. \angle AEB\cong\angle BAE & 7. Transitive property of equality \\
8. \overline{EB}\cong\overline{AB} & 8. From 7. $\Delta ABE$ is isosceles \\
9. EB = AB & 9. De(finition of congruence \\ 10. $\frac{AD}{DC}=\frac{EB}{BC}$ & 10. Triangle proportionality theorem \\
11. $\frac{AD}{DC}=\frac{AB}{BC}$ & 11. Substitution Property of equality \\[1ex] 
\end{tabular}

7 0
3 years ago
Read 2 more answers
Can someone please help me. I will give you brainliest, I’m struggling bad...
zhenek [66]

Step-by-step explanation:

as the other guy say it a for real

3 0
3 years ago
Find the least number which must be added to 6203 to obtain a perfect square.
andrey2020 [161]

Answer:

79

Step-by-step explanation:

       78

         ---------

7 |       62 03 

          49

         ----------

148 |   13 03

          11 84

         -----------

            19

         -----------

78^2 = 6084.

We observe that 78^2 < 6203.

79^2 = 6241.

We observe that 79^2 > 6203.

Hence the number to be added to 6203 is 6241 - 6203 = 38.

6203 + 38 = 3241

                  = 79 * 79

                  = 79.

Therefore 38 should be added to 6203 to obtain a perfect square.

5 0
3 years ago
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