The function sequalsf(t) gives the position of a body moving on a coordinate line, with s in meters and t in seconds. Find the
1 answer:
Answer:
Δs=10m
5m/s
Step-by-step explanation:
s=t²+3t +5,0<=t<=2
Let f(t)=s=t²+3t +5
The displacement of the body over the time interval from 0 to 2 is
Δs=f(2)-f(0)
Δs=(2²+3(2) +5) - (0²+3(0) +5)
Δs=10m
The average velocity of the body over the time interval from 0 to 2 is
displacement / travel time =Δs/Δt
=10 / 2
=5m/s
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