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FinnZ [79.3K]
4 years ago
12

The function sequals​f(t) gives the position of a body moving on a coordinate​ line, with s in meters and t in seconds. Find the

​ body's displacement and average velocity for the given time interval. sequals6t squaredplus3tplus5​, 0 less than or equalsxless than or equals2
Mathematics
1 answer:
tia_tia [17]4 years ago
8 0

Answer:

Δs=10m

v_a_v=5m/s

Step-by-step explanation:

s=t²+3t +5,0<=t<=2

Let f(t)=s=t²+3t +5

The displacement of the body over the time interval from 0 to 2 is

Δs=f(2)-f(0)

Δs=(2²+3(2) +5) - (0²+3(0) +5)

Δs=10m

The average velocity of the body over the time interval from 0 to 2 is

v_a_v=displacement / travel time =Δs/Δt

      =10 / 2

      =5m/s

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Please help ASAP thanks
hjlf

Answer:

x = 2.5 inches. Or

x = 5/2

Step-by-step explanation:

Length: 7 + 2x

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Note that you have to add x at each end of the picture and onto each part of the width.

The entire area is 120 square inches.

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x = 5/2

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Please answer this correctly
Andrej [43]
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