The function sequalsf(t) gives the position of a body moving on a coordinate line, with s in meters and t in seconds. Find the
1 answer:
Answer:
Δs=10m
5m/s
Step-by-step explanation:
s=t²+3t +5,0<=t<=2
Let f(t)=s=t²+3t +5
The displacement of the body over the time interval from 0 to 2 is
Δs=f(2)-f(0)
Δs=(2²+3(2) +5) - (0²+3(0) +5)
Δs=10m
The average velocity of the body over the time interval from 0 to 2 is
displacement / travel time =Δs/Δt
=10 / 2
=5m/s
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- 16 acres of barley only (no acres of wheat)
Step-by-step explanation:
A graph shows cost of planting puts an upper limit on planted area. The lower limit is provided by the requirement to plant at least 15 acres. The vertices of the feasible solution region are ...
(wheat acres, barley acres) = {(0, 15), (0, 16), (3, 12)}
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for (0, 16): 16·350 = 5600
for (3, 12): 3·450 +12·350 = 1350 +4200 = 5550
To maximize profit, the farmer should plant 16 acres of barley.
