Find the value of x. l || m. the diagram is not to scale

Write a polynomial function of least degree with integral coefficients that has the

frutty [35]

A polynomial function of least degree with integral coefficients that has the

given zeros $f(x)=x^4+x^3+9x^2+9x$

Given

Given zeros are 3i, -1 and 0

complex zeros occurs in pairs. 3i is one of the zero

-3i is the other zero

So zeros are 3i, -3i, 0 and -1

Now we write the zeros in factor form

If 'a' is a zero then (x-a) is a factor

the factor form of given zeros

$\:\left(x-3i\right)\left(x-\left(-3i\right)\right)\left(x-0\right)\left(x-\left(-1\right)\right)\\\left(x-3i\right)\left(x+3i\right)\left(x-0\right)\left(x+1\right)$

Now we multiply it to get the polynomial

$x\left(x-3i\right)\left(x+3i\right)\left(x+1\right)\\x\left(x^2+9\right)\left(x+1\right)\\x\left(x^3+x^2+9x+9\right)\\x^4+x^3+9x^2+9x$

polynomial function of least degree with integral coefficients that has the

given zeros $f(x)=x^4+x^3+9x^2+9x$

Learn more : brainly.com/question/7619478

6 0

3 years ago

PLZ HELP ME WITH THIS I NEED HELP ASAP

ValentinkaMS [17]

Answer:

See below

Step-by-step explanation:

Part A: $125 is constant.

PART B: Earning depends on hour

5 0

3 years ago

PLEASE HELP WILL GIVE BRAINLIEST!!!The table below represents the closing prices of stock ABC for the last five days

irakobra [83]

Answer:

A. $y=-8.583x+475.215$

Step-by-step explanation:

We are given,

The table representing the closing prices of stock for the last five days is,

Day Value

1 472.08

2 454.26

3 444.95

4 439.49

5 436.55

Using the linear regression calculator, we have that,

<h3>The linear equation that best fits the data is $y=-8.583x+475.215$ </h3>

Thus, option A is correct.

5 0

3 years ago

HELP ME I WILL GUVE BRAINLEST PLEASE THE ITHER GUY DID IT WRONG

laila [671]

Uppose the fence was 350 ft from home plateAt what height was each ball when it

over the ?

4 0

2 years ago

A manager at a local company asked his employees how many times they had given blood in the last year. The results of the survey

Lubov Fominskaja [6]

Answer:

$Var(X) = E(X^2) -[E(X)]^2 = 4.97 -(1.61)^2 =2.3779$

And the deviation would be:

$Sd(X) =\sqrt{2.3779}= 1.542 \approx 1.54$

Step-by-step explanation:

For this case we have the following distribution given:

X 0 1 2 3 4 5 6

P(X) 0.3 0.25 0.2 0.12 0.07 0.04 0.02

For this case we need to find first the expected value given by:

$E(X) = \sum_{i=1}^n X_i P(X_I)$

And replacing we got:

$E(X)= 0*0.3 +1*0.25 +2*0.2 +3*0.12 +4*0.07+ 5*0.04 +6*0.02=1.61$

Now we can find the second moment given by:

$E(X^2) =\sum_{i=1}^n X^2_i P(X_i)$

And replacing we got:

$E(X^2)= 0^2*0.3 +1^2*0.25 +2^2*0.2 +3^2*0.12 +4^2*0.07+ 5^2*0.04 +6^2*0.02=4.97$

And the variance would be given by:

$Var(X) = E(X^2) -[E(X)]^2 = 4.97 -(1.61)^2 =2.3779$

And the deviation would be:

$Sd(X) =\sqrt{2.3779}= 1.542 \approx 1.54$

8 0

4 years ago