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kap26 [50]
3 years ago
8

What is the solution to this expression

rac%7Bx%7D%7Bt%5E%7B2%7D%20%7D" id="TexFormula1" title="\frac{4}{x^{2} \cdot t} \frac{x}{t^{2} }" alt="\frac{4}{x^{2} \cdot t} \frac{x}{t^{2} }" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
ankoles [38]3 years ago
6 0

Answer:

4/xt 3 sqaured

Step-by-step explanation:

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Simplify (x2 16)(x2 16) = ?<br> a. x4 256<br> b. x4 32<br> c. x4 32<br> d. x4 256
vazorg [7]
A, and B look the same so you can choose, but the answer is <span>256<span>x4</span></span>
8 0
3 years ago
Sue initially has 5 hours of pop music and 4 hours of classical music in her collection. Every month onwards, the hours of pop m
Snezhnost [94]
<h2>Answer</h2>

f(x) = 5(1.25)x + 4

<h2>Explanation</h2>

To solve this, we are going to use the standard exponential equation:

f(x)=a(1+b)^x

where

a is the initial amount

b is the growth rate in decimal form

x is the time (in months for our case)

Since the hours of classic music remain constant, we just need to add them at the end. We know form our problem that Sue initially has 5 hours of pop, so a=5; we also know that every month onward, the hours of pop music in her collection is 25% more than what she had the previous month, so b=\frac{25}{100} =0.25. Now let's replace the values in our function:

f(x)=a(1+b)^x

f(x)=5(1+0.25)^x

f(x)=5(1.25)^x

Now we can add the hours of classical music to complete our function:

f(x)=5(1.25)^x+5

6 0
3 years ago
Read 2 more answers
Scatterplot Data y 3 5 7 BO 10 10 Question: 1. Use the data in the table to create a scatterplot 2. Would a linear model be appr
Wewaii [24]

Answer:

c i think

Step-by-step explanation:

8 0
3 years ago
Y = 2x – 1<br><br> Please help
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Positive 2 is your slope, (rise over run) if you have to graph it and -1 is your y-intercept
5 0
3 years ago
as the schools sign language interpreter kiran gets paid 35.50 for every parent-teacher conference that he attends. He also gets
yKpoI14uk [10]

<u>The interpreter attended </u><u>22 parent-teacher conference</u><u> and </u><u>5 school related assembly</u>

To solve this problem, we would write out two set of linear equations.

The data given on this problem are

  • parent-teacher conference = $35.50
  • school related assembly = $42
  • The total number of engagements = 27

Let x represent the number of parent-teacher conference

let y represent the number of school related conference

<h3>Equations</h3><h3>x+y = 27...equation (i)\\35.50(x)+42y=991...equation(ii)</h3>

From equation (i)

x+y  = 27\\x = 27-y...equation(iii)\\

Put equation(iii) into equation (ii)

35.50x+42y=991\\35.50(27-y)+42y=991\\958.50-35.50y+42y=991\\6.50y=991-958.50\\y=5

Put y = 5 into equation 1

x+y=27\\y = 5\\x+5=27\\x=27-5\\x=22

From the above calculations, he attended 22 parent-teacher conference and 5 school related assembly.

Learn more on linear equations here;

brainly.com/question/4074386

8 0
2 years ago
Read 2 more answers
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