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kap26 [50]
3 years ago
8

What is the solution to this expression

rac%7Bx%7D%7Bt%5E%7B2%7D%20%7D" id="TexFormula1" title="\frac{4}{x^{2} \cdot t} \frac{x}{t^{2} }" alt="\frac{4}{x^{2} \cdot t} \frac{x}{t^{2} }" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
ankoles [38]3 years ago
6 0

Answer:

4/xt 3 sqaured

Step-by-step explanation:

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3 years ago
Find the probability of each event.
jeka57 [31]

Using the binomial distribution, it is found that there is a 0.0108 = 1.08% probability of the coin landing tails up at least nine times.

<h3>What is the binomial distribution formula?</h3>

The formula is:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • The coin is fair, hence p = 0.5.
  • The coin is tossed 10 times, hence n = 10.

The probability that is lands tails up at least nine times is given by:

P(X \geq 9) = P(X = 9) + P(X = 10)

In which:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 9) = C_{10,9}.(0.5)^{9}.(0.5)^{1} = 0.0098

P(X = 10) = C_{10,10}.(0.5)^{10}.(0.5)^{0} = 0.001

Hence:

P(X \geq 9) = P(X = 9) + P(X = 10) = 0.0098 + 0.001 = 0.0108

0.0108 = 1.08% probability of the coin landing tails up at least nine times.

More can be learned about the binomial distribution at brainly.com/question/24863377

#SPJ1

5 0
1 year ago
How do you answer these questions
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3 years ago
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Which equation is correct
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3 years ago
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What is the value of x
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Answer:

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Step-by-step explanation:

3x+2

3(11)+2

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35

6 0
2 years ago
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