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3 years ago

8

What is the solution to this expression

rac%7Bx%7D%7Bt%5E%7B2%7D%20%7D" id="TexFormula1" title="\frac{4}{x^{2} \cdot t} \frac{x}{t^{2} }" alt="\frac{4}{x^{2} \cdot t} \frac{x}{t^{2} }" align="absmiddle" class="latex-formula">

1 answer:

ankoles [38]3 years ago

6 0

Answer:

4/xt 3 sqaured

Step-by-step explanation:

You might be interested in

4,357.25 rounded two decimal places

Amiraneli [1.4K]

Answer:

$4357.25$

Step-by-step explanation:

Given the following question:

$4357.25$
$4357.250$
$0$
$=4357.25$

The following number is already rounded two decimal places which means the answer is "4357.25."

In case you meant one decimal place....

$4357.25$
$5=5$
$=4357.3$

Hope this helps.

3 0

2 years ago

Determine if the sequence below is arithmetic or geometric and determine the

algol13

9514 1404 393

Answer:

r = 2

Step-by-step explanation:

The first differences between successive terms are ...

10 -5 = 5

20 -10 = 10

The differences are not constant, so the sequence is NOT arithmetic.

__

The ratios of successive terms are ...

10/5 = 2

20/10 = 2

The ratios are constant, so the sequence is ...

geometric with a common ratio of 2.

4 0

2 years ago

In a semiconductor manufacturing process, three wafers from a lot are tested. Each wafer is classified as pass or fail. Assume t

Angelina_Jolie [31]

Answer:

$P(X = 0) = 0.027$

$P(X = 1) = 0.189$

$P(X = 2) = 0.441$

$P(X = 3)= 0.343$

Step-by-step explanation:

The probability mass function P(X = x) is the probability that X happens x times.

When n trials happen, for each $x \leq n$ , the probability mass function is given by:

$P(X = x) = pe_{n,x}.p^{x}.(1-p)^{n-x}$

In which p is the probability that the event happens.

$pe_{n,x},$ is the permutation of n elements with x repetitions(when there are multiple events happening(like one passes and two not passing)). It can be calculated by the following formula:

$pe_{n,x} = \frac{n!}{x!}$

The sum of all P(X=x) must be 1.

In this problem

We have 3 trials, so $n = 3$

The probability that a wafer pass a test is 0.7, so $p = 0.7$

Determine the probability mass function of the number of wafers from a lot that pass the test.

$P(X = 0) = (0.7)^{0}.(0.3)^{3} = 0.027$

$P(X = 1) = pe_{3,1}.(0.7).(0.3)^{2} = 0.189$

$P(X = 2) = pe_{3,2}.(0.7)^{2}.(0.3) = 0.441$

$P(X = 3) = (0.7)^{3} = 0.343$

5 0

3 years ago

What are the factors of 21

sweet-ann [11.9K]

Answer:

21: 3and 7 factors

54: 6and 9 factors

3 0

3 years ago

What’s the correct answer for this?

earnstyle [38]

Answer:

6

Explanation:

According to secant-secant theorem,

(PB)(PA)=(PD)(PC)

(7)(12)=(PD)(14)

NOW

84/14 = PD

PD = 6

4 0

3 years ago