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wolverine [178]
3 years ago
8

Which expression is equivalent to x^4 - 12x^2 + 36?

Mathematics
2 answers:
Kobotan [32]3 years ago
4 0

Answer:

(1) (x^2 - 6)(^x2 - 6)

Good luck !!

QveST [7]3 years ago
3 0
So the answer is
(<span>x^2 plus or minus 6)(x^2 plus or minus 6)
an easy way to do this is to only look at plus or minus 6
x^4 <u><em>- 12</em></u>x^2 + <u><em>36   (-12 and 36)
</em></u><em />

<u><em /></u>6 x 6 = 36
<em />6 + 6 </span>≠ -12              (x^2 + 6)(x^2 + 6) is incorrect        
<span><u><em>
</em></u><em><u /></em><u />
6 x -6 </span>≠ 36
<span><em />6 + -6 </span>≠ -12             (x^2 - 6)(x^2 + 6) is incorrect
<span><em /><em>
</em><em />-6 x -6 = 36
<em />-6 + -6 = -12         </span><span>(x^2 - 6)(x^2 - 6) is correct
</span><u><em>
the answer is (1)

</em></u>
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Given: 
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Area of a semi-circle = (π r²)/2

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3 0
3 years ago
Hence solve the equation x^3+x^2-6x=0<br>​
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<em>Answer:</em>

<em />

<em>x³ + x² - 6x = 0</em>

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<em>x(x² + 3x - 2x - 6) = 0</em>

<em>x[x(x + 3) - 2(x + 3)] = 0</em>

<em>x(x - 2)(x + 3) = 0</em>

<em>x₁ = 0</em>

<em>x - 2 = 0 => x₂ = 2</em>

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The sum of the first four terms of an arithmetic sequence is $10$. If the fifth term is $5$, what is the sixth term?
Nookie1986 [14]

The sixth term of an arithmetic sequence is 6

<h3>How to find arithmetic sequence?</h3>

The sum of the first four terms of an arithmetic sequence is 10.

The fifth term is 5.

Therefore,

sum of term = n / 2(2a + (n - 1)d)

where

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Therefore,

n = 4

10 = 4 / 2 (2a + 3d)

10 = 2(2a + 3d)

10 = 4a + 6d

4a + 6d = 10

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a = 1

Therefore,

6th term = a + 5d

6th term = 1 + 5(1)

6th term = 6

learn more on sequence here: brainly.com/question/24128922

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