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wariber [46]
3 years ago
6

Round 18.2 to 1 significant figure

Mathematics
2 answers:
notsponge [240]3 years ago
6 0
The answer would be : 18.0

Hope this helps !

Photon
Andrej [43]3 years ago
5 0
Hello there.

Round 18.2 to 1 significant figure

Answer: It would be 18.

Hope This Helps You!
<span>Good Luck Studying ^-^</span>
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PLEASE SOLVE FOR B. PLEASE HELP VERY URGENT!
aleksklad [387]

Answer:

b1 = (2A/ h) - b2

Step-by-step explanation:

A  = 1/2 h(b1 + b2)

b1 + b2 = A / 1/2h = 2A/h

b1 = (2A/ h) - b2

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3 years ago
Consider the parabola given by the equation: f(x) = 2x2 + 14.0 – 4
Softa [21]

Answer:

Step-by-step explanation:

f(x)  = 2x² + 14x - 4

= 2(x² + 7x) - 4

= 2(x² +7x + 3.5²) - 2(3.5²) - 4

= 2(x+3.5)² - 28.5

vertex (3.5, -28.5) = (7/2, -57/2)

The vertical intercept is the y-intercept, i.e., f(0) = -4.

The x-intercepts are the values of x for which y=0.

2x² + 14x - 4  = 0

x = [-14±√(14²-4(2)(-4))]/[2(2)] = [-7±√57]/2 ≅ -7.27, 0.27

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3 years ago
The radius of a circle r in centimeters can be found by solving r to the second power = 70. What is the radius of the circle r,
slavikrds [6]

Answer:

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3 years ago
A bouncing ball reaches a height of 54 inches at its first peak, 36 inches at its second peak, and 24 inches at its third peak.
sesenic [268]

Answer:

f(x) = 54(two-thirds) Superscript x minus 1

Step-by-step explanation:

Given that:

First peak : 36 / 54=2/3

Second peak : 24 / 36 = 2/3

The common ratio here is 2/3 ; which mean each bounce height is 2/3 of previous height

Modeling this using geometric progression :

An=a1r^(n-1)

An = nth term of a geometric progression

a1=first term

r=common ratio = 2/3

n = nth term

a1=54

Substituting into the above formular :

An=54(2/3)^(n-1)

4 0
2 years ago
Read 2 more answers
canning operation is designed to fill cans with 14.5 oz of ingredients, on average, with a standard deviation of 0.1 oz. Nine ca
Pavlova-9 [17]

Answer:

SE = 0.025

Step-by-step explanation:

We are given;

Sample mean; x¯ = 14.52

Sample standard deviation; s = 0.075

Sample size; n = 9

Now,formula for standard error of sample mean is;

SE = s/√n

SE = 0.075/√9

SE = 0.075/3

SE = 0.025

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3 years ago
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