1. c. 35
2. <span>d. 1.26 x 10^24 molecules
3. </span><span>d. 303.6 g</span>
Answer:
(a)The molar mass of the gene fragment is 18220.071g/mol = 18.22 kg/mol
(b)The freezing point for the aqueous solution is
C
Explanation:
The osmotic pressure (π) is given by the following equation:

= Concentration of solution
R = universal gas constant = 62.364 
T = temperature
Weight of solute = w = 10.0 mg
Let the molecular weight of the solute be m g/mol.
Concentration = 

m = 18220.071g/mol
Therefore, the molar mass of the gene fragment is 18220.071g/mol = 18.22 kg/mol

m is the molality of the solution.
m =
mol/kg

=
C
The freezing point for the aqueous solution is
C
You can titrate a sample of the vinegar with a known standard of NaOH. The pH at the equivalence point is determined by the hydrolysis of the salt
<span>Open the bleeder valve during filling</span>
Answer:
Microliters = 
Explanation:
SI unit of volume is liter.
..............................(1)
1dm=10cm
.................(2)
replacing value of
from equation (1) in equation (2)
...................(3)
but
....................(4)
replacing value of 1 liter from equation (3) in equation (4)

on solving further ,we get



Microliters = 