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tiny-mole [99]
3 years ago
7

What were the first 25 elements that found in the earth? answer it plz. ​

Chemistry
1 answer:
ollegr [7]3 years ago
6 0

Answer:

Copper, Lead, Gold, Silver, Iron, Carbon, Tin, Sulfur, Mercury, Zinc, Arsenic, Bismuth, Phosphorus, Cobalt, Platinum, Nickel, Magnesium, Hydrogen, Oxygen,  Nitrogen, Barium, Chlorine,  Manganese, Molybdenum, Tungsten.

Explanation:

Hope This Helps :b

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Heating galactose, a monosaccharide sugar, in the presence of excess oxygen produces carbon dioxide gas and water vapor. Classif
artcher [175]

Answer:

it's a combustion reaction

6 0
3 years ago
(Please answer ASAP) Describe in your own words A.) what does Inert mean? B.) why are noble gases Inert (include an explanation
Alex_Xolod [135]
Inert means unreactive in nature or un reactive in there normal or natural state
and noble gas has there outermost shell electron filled up they complete there duplet or oclet valency state that why there inert in there natural state
4 0
4 years ago
Convert 14.72 kg to ____ mg
navik [9.2K]

Answer:

14720000

Explanation:

1 kg = 1000000 mg

14.72 kg = 14.72 x 1000000

=14720000

Please Mark me brainliest

6 0
3 years ago
What part of a circuit stops the current if it is open
eduard

Answer:

B is the correct answer

Explanation:

Just is

8 0
3 years ago
Find the mass in grams of 3.00 x 1023 molecules of F2
LUCKY_DIMON [66]
<h3>Answer:</h3>

18.9 g F₂

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<h3>Explanation:</h3>

<u>Step 1: Define</u>

3.00 × 10²³ molecules F₂

<u>Step 2: Identify Conversions</u>

Avogadro's Number

Molar Mass of F₂ (Diatomic) - 38.00 g/mol

<u>Step 3: Convert</u>

  1. Set up:                              \displaystyle 3.00 \cdot 10^{23} \ molecules \ F_2(\frac{1 \ mol \ F_2}{6.022 \cdot 10^{23} \ molecules \ F_2})(\frac{38.00 \ g \ F_2}{1 \ mol F_2})
  2. Multiply:                                                                                                             \displaystyle 18.9306 \ g \ F_2

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

18.9306 g F₂ ≈ 18.9 g F₂

8 0
3 years ago
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