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3 years ago

A family has a gross monthly income of $4395. Their monthly home mortgage payment is $1896. In general,

1 answer:

7 0

28% of $4395 would be closer to $1230 meaning that the family is indeed spending quite a bit more than the recommended amount on their home mortgage

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Which equation has no solution?

Nuetrik [128]

The third one.

Because the answer of the absulate value equations is always positive.

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2 years ago

Read 2 more answers

Determine whether the triangles are similar. If so, what are the similarity statement and the postulate or theorem used?

boyakko [2]

The answer is d
sides and angles show similarity

4 0

2 years ago

What is the equivalent rate of 9/15/18?

Nimfa-mama [501]

Here, the number is = 9/15/18
We can re-write it as: 9 /15*18 = 9/270 = 1/30

In short, Your Answer would be 1/30

Hope this helps!

6 0

3 years ago

A stationary store has decided to accept a large shipment of ball-point pens if an inspection of 17 randomly selected pens yield

Leno4ka [110]

Answer:

0.762 = 76.2% probability that this shipment is accepted

Step-by-step explanation:

For each pen, there are only two possible outcomes. Either it is defective, or it is not. The probability of a pen being defective is independent from other pens. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

17 randomly selected pens

This means that $n = 17$

(a) Find the probability that this shipment is accepted if 10% of the total shipment is defective. (Use 3 decimal places.)

This is $P(X \leq 2)$ when $p = 0.1$ . So

$P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{17,0}.(0.1)^{0}.(0.9)^{17} = 0.167$

$P(X = 1) = C_{17,1}.(0.1)^{1}.(0.9)^{16} = 0.315$

$P(X = 2) = C_{17,2}.(0.1)^{2}.(0.9)^{15} = 0.280$

$P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.167 + 0.315 + 0.280 = 0.762$

0.762 = 76.2% probability that this shipment is accepted

8 0

3 years ago

Please helppp ;-; how do you determine the end behavior of a function?

Karolina [17]

Answer:

End Behavior of a Function. The end behavior of a polynomial function is the behavior of the graph of f( x ) as x approaches positive infinity or negative infinity. The degree and the leading coefficient of a polynomial function determine the end behavior of the graph.

Step-by-step explanation:

3 0

2 years ago