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3 years ago

8

Kelly made six batches of cookies. Her friends asked her to make an extra batch. She used 17 1/4 cups of sugar and needs another

7/8cups for the extra batch. How many cups of sugar will Kelly use altogether?

1 answer:

bixtya [17]3 years ago

4 0

Answer:

18 1/8

Step-by-step explanation:

Just simple fraction addition.

17 1/4+ 7/8

Make common denominator

17 2/8+7/8

17 9/8 which is 18 1/8

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For this one can you also tell me if my answer to question one is right!

kipiarov [429]

2. Tuesday
3.1/7 and 0.14
4. neither likely or unlikely because most days occur 52 times through out the year.
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2 years ago

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The pool at "Splash Around" is open for 14 weeks during the summer. You can swim for $6 a session, or you can buy a membership f

iris [78.8K]

Price before membership= price 1 = $6
price after membership = price 2 = $4
Membership price = $100
SO according to price 1 and price 2; price after membership saves up $2 for each session.
Hence to justify the price of membership number of sessions can be calculated as follows:-
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3 years ago

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Suppose a Hispanic Heritage festival is held in an area measuring 2,494 square yards. If the length of the festival is 58 yards,

Kaylis [27]

Answer: 43 yards.

Step-by-step explanation:

Let the shape of the area occupied for festival be rectangle.

and area of rectangle = length x width

Given: Area of the festival= 2,494 square yards.

Length of the festival= 58 yards

Then width = (Area )÷ (length)

= (2494)÷58 yards

= 43 yards

hence, the width of the festival = 43 yards.

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2 years ago

Women athletes at the a certain university have a long-term graduation rate of 67%. Over the past several years, a random sample

lana [24]

Answer:

$z=\frac{0.579 -0.67}{\sqrt{\frac{0.67(1-0.67)}{38}}}=-1.193$

$p_v =P(z$

So the p value obtained was a very high value and using the significance level given $\alpha=0.1$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can conclude that the proportion of women athletes graduated is not significantly lower than 0.67 or 67% at 10% of significance

Step-by-step explanation:

Data given and notation

n=38 represent the random sample taken

X=22 represent the number of women athletes graduated

$\hat p=\frac{22}{38}=0.579$ estimated proportion of women athletes graduated

$p_o=0.67$ is the value that we want to test

$\alpha=0.1$ represent the significance level

Confidence=90% or 0.90

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion is lower than 0.67 or no:

Null hypothesis: $p \geq 0.67$

Alternative hypothesis: $p < 0.67$

When we conduct a proportion test we need to use the z statisitc, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.579 -0.67}{\sqrt{\frac{0.67(1-0.67)}{38}}}=-1.193$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.1$ . The next step would be calculate the p value for this test.

Since is a left tailed test the p value would be:

$p_v =P(z$

So the p value obtained was a very high value and using the significance level given $\alpha=0.1$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can conclude that the proportion of women athletes graduated is not significantly lower than 0.67 or 67% at 10% of significance

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2 years ago

7(3x-1)-6(2x+3)=8(x-2)+1

Vitek1552 [10]

Answer:

X equals 10

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