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3 years ago

I need help with my homework, the information given to me wasn't helping.

Mathematics

1 answer:

dsp733 years ago

7 0

1) This is not a linear equation as it curves and thus has acceleration and thus its velocity is not constant. You COULD find a linear least squares equation, but I do not think that that is what they want you to do, and the least squares regression is still only an approximation...so I would say that you cannot write a linear equation for the graph.

2) The y-intercept is the value of y when x=0, and this point is clearly marked as the point (0,1)

3) The slope of a line can be found using any two points on the line and it will be equal to:

m=slope=(y2-y1)/(x2-x1)...in this case:

m=(2-1)/(2--3)=1/5 so the line has a slope of 1/5

4) To find the y-intercept precisely we start with the slope that we found earlier and use that value in the slope-intercept form of a line, y=mx+b, and since m=1/5 we have:

y=x/5+b, where b is the y-intercept and using (2,2) we can solve for b...

2=2/5+b

10/5=2/5+b

b=8/5 or if you prefer 1 3/5 or 1.6

So the y-intercept is 8/5, 1 3/5, or 1.6 depending on how you'd like to use it.

5) We have already found b and m of the y=mx+b so the equation of this line is:

y=x/5+8/5 or more neatly

y=(x+8)/5

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The equation of four lines are given below:

tia_tia [17]

Answer:

epic

Step-by-step explanation:

5 0

3 years ago

The height of a triangle is 5 cm shorter than its base. If the area of the triangle is 25 cm2, find the height of the triangle.

Olin [163]

Answer:

$h = 5\ cm$

Step-by-step explanation:

Let's call B at the base of the triangle and call h at the height of the triangle. Then we know that:

The height of a triangle is 5 cm shorter than its base. This means that:

$h = B-5$ .

The area of the triangle is 25 cm²

By definition the area of a triangle is:

$A = 0.5Bh$

For this triangle we know that $A = 25\ cm^2$ and $h = B-5$ . We substitute these values in the equation and solve for B.

$25 = 0.5B (B-5)$

$0.5B ^ 2-\frac{5}{2}B-25 = 0$

Now we use the quadratic formula to solve the equation.

For an equation of the form $ax ^ 2 + bx + c = 0$ the quadratic formula is:

$B=\frac{-b\±\sqrt{b^2-4ac}}{2a}$

In this case note that: $a=0.5,\ \ b=-\frac{5}{2}\ \ c=-25$

Then:

$B=\frac{-(-\frac{5}{2})\±\sqrt{(-\frac{5}{2})^2-4(0.5)(-25)}}{2(0.5)}$

$B=\frac{\frac{5}{2}\±\sqrt{\frac{25}{4}+50}}{1}$

$B=\frac{5}{2}\±\frac{15}{2}$

The solutions are:

$B_1=\frac{5}{2}+\frac{15}{2}=10$

$B_2=\frac{5}{2}-\frac{15}{2}=-5$

For this problem we take the positive solution.

$B=10\ cm$

Now we substitute the value of B in the equation to find the height h

$h = 10-5$

$h = 5\ cm$

6 0

3 years ago

PLEASE HELP!!!! WILL MARK BRAINLIEST!!!!

irga5000 [103]

Answer:

None of these.

Step-by-step explanation:

Let's assume we are trying to figure out if (x-6) is a factor. We got the quotient (x^2+6) and the remainder 13 according to the problem. So we know (x-6) is not a factor because the remainder wasn't zero.

Let's assume we are trying to figure out if (x^2+6) is a factor. The quotient is (x-6) and the remainder is 13 according to the problem. So we know (x^2+6) is not a factor because the remainder wasn't zero.

In order for 13 to be a factor of P, all the terms of P must be divisible by 13. That just means you can reduce it to a form that is not a fraction.

If we look at the first term x^3 and we divide it by 13 we get $\frac{x^3}{13}$ we cannot reduce it so it is not a fraction so 13 is not a factor of P