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VikaD [51]
3 years ago
5

The temperature in degrees Celsius is 273.15 less than the temperature in kelvin. Andrew is conducting a science experiment wher

e the temperature must be kept between 13.5°C and 18.5°C. Andrew wants to know the range of the temperature in kelvin.
Select all of the whole number temperatures, in kelvin, at which Andrew can conduct his experiment.
Mathematics
1 answer:
Stella [2.4K]3 years ago
3 0

Answer:

The whole number temperatures, in kelvin, at which Andrew can conduct his experiment are 287, 288, 289,290,291.

Step-by-step explanation:

The temperature in degrees Celsius is 273.13 less than the temperature in kelvin; mathematically this means:

k=c+273.15

Where k is the temperature in kelvin and c is the temperature in Celsius.

From this relationship we convert Andrew's temperature range—

13.5°c to 18.5°c—to kelvin:

k_1=13.5^oc+273.15=286.65

k_2=18.5^oc+273.15=291.65

Thus Andrew can conduct his experiment between 286.65 and 291.65 kelvin, and the whole number temperatures between these extremes are 287, 288, 289,290,291.

Thus the whole number temperatures, in kelvin, at which Andrew can conduct his experiment are 287, 288, 289,290,291.

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Answer:

18 km/hr

Step-by-step explanation:

To find the unit rate, we must find the rate in kilometers per hour.

Let’s divide the total kilometers by the total number of hours.

unit rate = kilometers/hours

Juan rode 72 kilometers in 4 hours.

unit rate = 72 kilometers/ 4 hours

unit rate = 72 km/4 hrs

unit rate = 18 km / hr

The unit rate is 18 kilometers per hour.

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7 0
3 years ago
PLEASE HELP Given: △KLM LM=12, m∠K=60°, m∠M=45° Find: Perimeter of △KLM.
worty [1.4K]

We have to find the perimeter of the triangle KLM.

We have been given that the length of the side LM=12, m\angleK=60^\circ, and m\angle M= 45^\circ

Refer the attached image.

In a triangle sum of three angles should be 180^\circ.

So,

m\angle K+m\angle L+m\angle M=180^\circ

Plugging the values of angle K and angle M, we get:

60^\circ+m\angle L+45^\circ=180^\circ

So,

m\angle L=180^\circ-105^\circ=75^\circ

Now, that we have the measure of angle L, we will apply sine rule to find the length of the sides KL and KM.

Using the sine law for the triangle KLM, we get:

\frac{sin K}{LM}=\frac{sin L}{KM}=\frac{sin M}{KL}

Refer the image. Plugging the value of the sides of the triangle KLM and the angles of the triangle KLM, we get:

\frac {sin 60^\circ}{12}=\frac{sin 75^\circ}{y}=\frac{sin 45^\circ}{x}

Now using,

\frac {sin 60^\circ}{12}=\frac{sin 75^\circ}{y}

We get the value of 'y'

y=\frac{sin 75^\circ}{sin 60^\circ} \times 12=\frac{0.9659}{0.866} \times 12=13.38

So the length of the side KM is 13.38 units.

Now using,

\frac {sin 60^\circ}{12}=\frac{sin 45^\circ}{x}

We get the value of 'x'

x=\frac{sin 45^\circ}{sin 60^\circ} \times 12=\frac{0.707}{0.866} \times 12=9.79

So the length of the side KL is 9.79 units.

Now, to find the perimeter of the triangle KLM we need to sum up the length of the sides of the triangle KLM.

The perimeter of the triangle KLM = KL+ LM + KM = 9.79 + 12 + 13.38 = 35.17 units

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A water faucet is turned 1/7 to the right and then 3/4 to the right again. How far is the water faucet turned?
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Answer:

A water faucet is turned 1/7 to the right and then 3/4 to the right again.

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Hope this helps!

:)

8 0
3 years ago
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