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Anastasy [175]
3 years ago
6

I’m sorry I’m bad at math and I need help

Mathematics
1 answer:
Natali [406]3 years ago
5 0

A or B

I'm confuseddd omg

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Solve for x by factoring X2-2x=35
valkas [14]
By factoring, x equals both -5 and 7.
7 0
4 years ago
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What is the area of the shape shown above
Mice21 [21]

Answer:

the area is 286

pls mark as brainlist

7 0
3 years ago
Read 2 more answers
Please answer this. thank you
Rama09 [41]

Answer:  (-\infty, -4]

Curved parenthesis at negative infinity

Square bracket at -4

====================================================

Work Shown:

5(x+4) \le 0 \\\\x+4 \le \frac{0}{5} \\\\x+4 \le 0 \\\\x \le 0-4 \\\\x \le -4 \\\\

The last inequality shown above is the same as saying -\infty < x \le -4

Converting this to interval notation leads to the final answer of (-\infty , -4]

Note the use of a square bracket at -4 to include this endpoint. We can never include either infinity, so we always use a parenthesis for either infinity.

5 0
3 years ago
Solve <br>|-4b-8|+|-1-b^2|+2b^3. b= -2<br>show steps please .
evablogger [386]
Ok, first put in the -2 for each b. That gives:
|-4(-2)-8|+|-1(-(-2))^2|+2(-2)^3
Let's do each section.
The first section is |-4(-2)-8)|
-4 times -2 is 8, minus 8 is 0. The absolute value of 0 is still 0.
Now we move on to |-1(-(-2))^2)|
First we do exponents
-(-2) is 2, and 2^2 is 4. 4 times -1 is -4. The absolute value of -4 is 4
Now the last section, 2(-2)^3
Exponents first: (-2)^3 is -2 * -2 * -2, which is -8.
-8*2=-16.
0+4+(-16)=-12
7 0
3 years ago
What are the solutions of ×^2=8-5×?
yaroslaw [1]

Answer:

x=8 & x=3

Step-by-step explanation:

We want to get the (x)s all on one side.

add 5x to each side

{x}^{2}  + 5x = 8

Since x^2 is x•x and 5x is 5•x then we can change the formula to

x(x+5)=8

then seperate that

x=8

x+5=8

subtract 5 from each side

x=3.

The solutions are 8 and 3.

7 0
3 years ago
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