What is the slope of a line parallel to the graph of y+1=-8(x-2)?
1 answer:
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x° = 14°, y° = 14°; Use vertical and supplementary angles.
Step-by-step explanation:
The image of the answer is attached below.
In the given image two lines are parallel with transversal.
(9x + 12)° and ∠1 are vertically opposite angles.
Vertically opposite angles are equal.
∠1 = (9x + 12)°
Consecutive interior angles are supplementary.
(9x + 12)° + 3x° = 180°
⇒ 12x° = 168°
⇒ x° = 14°
Sum of the adjacent angles in a line are supplementary.
3x° + (4y – 10)° = 180°
⇒ 3(14)° + 4y° – 10° = 180°
⇒ 4y° = 148°
⇒ y° = 14°
Hence, x° = 14°, y° = 14°; Use vertical and supplementary angles.
