Five raised to the fifth power 5^5 5*5*5*5*5 = 3,125
Let x be the smallest number.
x＋(x＋1)＋(x＋2)＝384
3x＋3＝384
3x＝381
x＝127
The three consecutive numbers are 127, 128 and 129.
Hope my answer helped u :)
Answer:
The answer is c definitely
<span> 3 to the 10th power over 3 to the 3rd power</span>
