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kolezko [41]
3 years ago
7

Write a linear function f with the given values. f(0) = 2. f(2) = 4

Mathematics
1 answer:
Ganezh [65]3 years ago
6 0

Answer:

<em> I Think this will be the answer, We need to write the equation of a line with the given values of $f(0)=2$ and $f(2)=4$. To write the equation of the line, we can use the slope-intercept ...</em>

<em />

Step-by-step explanation:

give brainiest

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Fittoniya [83]
X=3 or X=0
It’s one of these
6 0
3 years ago
Let f(x) = 3x^2 – 8x + 5 and let g(x) = 2x – 8. Find
fenix001 [56]

Answer:

B. 3x² – 10x + 13

Step-by-step explanation:

given:

f(x) = 3x² – 8x + 5

g(x) = 2x – 8

f(x) - g(x)

= (3x² – 8x + 5) - (2x – 8)

= 3x² – 8x + 5 - 2x + 8

= 3x² – 10x + 13

3 0
3 years ago
I’m slow , can i get help on this asap please ?
makkiz [27]
140°
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5 0
3 years ago
Copy the problems onto your paper, mark the givens and prove the statements asked. Given: ∠BTO ≅ ∠IWE WI ≅ BT , OW ≅ ET Prove: △
Varvara68 [4.7K]

Answer:

\triangle BOT \cong \triangle IEW

Step-by-step explanation:

We are given the following in the question:

\angle BTO \cong \angle IWE\\WI \cong BT\\OT \cong EW

We have to prove:

\triangle BOT \cong \triangle IEW

Proof:

\text{In }\triangle BOT \text{ and } \triangle IEW

we can write:

\angle BTO = \angle IWE\text{ (Given)}\\WI \cong BT\text{ (Given)}\\OT \cong EW\text{ (Given)}

Hence, the two triangle are congruent by SAS congruency rule.

\triangle BOT \cong \triangle IEW

The attached image shows the two triangle.

8 0
3 years ago
A random sample of 11 university students produced the following data, where x is the minutes spent studying per day, and y is t
SIZIF [17.4K]

Answer:

16.373,16.4

Step-by-step explanation:

Given that a  random sample of 11 university students produced the following data, where x is the minutes spent studying per day, and y is the first exam score (out of a maximum of 100 points).

x y

11 39

13 55

14 43

17 46

19 69

22 75

24 77

25 78

28 77

31 93

34 92 Observations 11        

       

ANOVA        

df SS MS F Significance F    

Regression 1 3214.095153 3214.095153 69.46052448 1.59367E-05    

Residual 9 416.4503017 46.27225574      

Total 10 3630.545455      

       

Coefficients Standard Error t Stat P-value Lower 95% Upper 95% Lower 95.0% Upper 95.0%

Intercept 16.37281677 6.48384963 2.525169105 0.0324919 1.705329914 31.04030362 1.705329914 31.04030362

x 2.369323595 0.28428592 8.33429808 1.59367E-05 1.726224167 3.012423023 1.726224167 3.012423023

We get regression line as y =2.369x+16.373

a) value of intercept = 16.373

b) 16.4

8 0
3 years ago
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