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3 years ago

-2(-5 - 2) + (2)/(3)

Mathematics

1 answer:

ikadub [295]3 years ago

6 0

Answer:

14 2/3 or 14.6 repeting

Step-by-step explanation:

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I am thinking of two numbers. The sum of the two is 10 and the difference is 2

mixer [17]

Answer:

4 and 6

Step-by-step explanation:

First, let's find all the pairs that add up to 10.

1 + 9, 2 + 8, 3 + 7, 4 + 6, and 5 + 5

Next, we find the difference between the addends for each pair.

9 - 1 = 8
8 - 2 = 6
7 - 3 = 4
6 - 4 = 2
5 - 5 = 0

As you can, see the numbers that add to 10 and have a different of 2 is 4 and 6.

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2 years ago

Students love to put ranch dressing on everything, so Elvira needs to keep plenty in stock. The students eat about 2.25 gallons

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In 48 days, they would have consumed 108 gallons, and have 22 left, so yeah. 48 days

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3 years ago

4(x + 1) − 7x = −3 (x − 1) + 1

grigory [225]

The apartment complex has 20 apartment per buildings 4 apartment are 3 bedroom apartment, 7 are 2 bedroom unit,and 9 apartment are 1 bedroom units.if the apartment complex builds 50 buildings how many 3 bedroom units would they have?

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3 years ago

A volcano erupted

IgorC [24]

Percentage decrease = d
h1 = 2950
h2 = 2550

d/100 = (h2-h1)/h1

d/100 = (2950-2550)/2950
d=13.56

3 0

3 years ago

let t : r2 →r2 be the linear transformation that reflects vectors over the y−axis. a) geometrically (that is without computing a

tangare [24]

(a) ( 1, 0 ) is the eigen vector for '-1' and ( 0, 1 ) is the eigen vector for '1'.

(b) two eigen values of 'k' = 1, -1

for k = 1, eigen vector is $\left[\begin{array}{c}0\\1\end{array}\right]$

for k = -1 eigen vector is $\left[\begin{array}{c}1\\0\end{array}\right]$

See the figure for the graph:

(a) for any (x, y) ∈ R² the reflection of (x, y) over the y - axis is ( -x, y )

∴ x → -x hence '-1' is the eigen value.

∴ y → y hence '1' is the eigen value.

also, ( 1, 0 ) → -1 ( 1, 0 ) so ( 1, 0 ) is the eigen vector for '-1'.

( 0, 1 ) → 1 ( 0, 1 ) so ( 0, 1 ) is the eigen vector for '1'.

(b) ∵ T(x, y) = (-x, y)

T(x) = -x = (-1)(x) + 0(y)

T(y) = y = 0(x) + 1(y)

Matrix Representation of $T = \left[\begin{array}{cc}-1&0\\0&1\end{array}\right]$

now, eigen value of 'T'

$T - kI = \left[\begin{array}{cc}-1-k&0\\0&1-k\end{array}\right]$

after solving the determinant,

we get two eigen values of 'k' = 1, -1

for k = 1, eigen vector is $\left[\begin{array}{c}0\\1\end{array}\right]$

for k = -1 eigen vector is $\left[\begin{array}{c}1\\0\end{array}\right]$

Hence,

(a) ( 1, 0 ) is the eigen vector for '-1' and ( 0, 1 ) is the eigen vector for '1'.

(b) two eigen values of 'k' = 1, -1

for k = 1, eigen vector is $\left[\begin{array}{c}0\\1\end{array}\right]$

for k = -1 eigen vector is $\left[\begin{array}{c}1\\0\end{array}\right]$

Learn more about " Matrix and Eigen Values, Vector " from here: brainly.com/question/13050052

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6 0

1 year ago