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3 years ago

-2(-5 - 2) + (2)/(3)

Mathematics

1 answer:

ikadub [295]3 years ago

6 0

Answer:

14 2/3 or 14.6 repeting

Step-by-step explanation:

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Larry has a cylinder shaped pitcher that is 13 inches long and a radius of 4 inches. Sandra has a cylinder shaped pitcher that i

puteri [66]

What do you need to find I need to know that so I can solve it

7 0

3 years ago

Very buys a basket of mangoes that is priced $14 before tax. The sales tax is 6%. What is the total price Avery pays for t

igor_vitrenko [27]

Answer:

Avery needs to pay $14.84

Step-by-step explanation:

When there's a tax we need to sum the original value of the product with the tax's value. To find the amount of money Avery needs to pay in taxes we can apply a rule of three as shown below:

$\frac{14}{x} = \frac{100}{6} \frac{\%}{\%}$

Where "x" is the tax value, and $14 represents 100%, since it's the value used to calculate the tax. We have:

$x = \frac{14*6}{100}\\x = \frac{84}{100}\\x = 0.84$

The value to be paid is the product value plus the tax, therefore:

$\text{paid} = 14 + 0.84 = 14.84$

Avery needs to pay $14.84

6 0

3 years ago

Solve the equation to find where the treste ground levelEnter your answers from least to greatest and round to the nearest The m

DaniilM [7]

Answer:

The trestle meets ground level at 0.875 units and 9.125 units

Step-by-step explanation:

Poorly formatted question.

The given equation is:

$y = -x^2 + 10x - 8$

Required

The point where the trestle gets to the ground level

To do this, we set $y = 0$

So, we have:

$-x^2 + 10x - 8 = 0$

Multiply through by -1

$x^2 -10x + 8 = 0$

Solve using quadratic formula:

$x= \frac{-b \± \sqrt{b^2 - 4ac}}{2a}$

Where:

$a = 1; b =-10; c = 8$

So, we have:

$x= \frac{-(-10) \± \sqrt{(-10)^2 - 4*1*8}}{2*1}$

$x= \frac{-(-10) \± \sqrt{68}}{2*1}$

$x= \frac{-(-10) \± 8.25}{2}$

$x= \frac{10 \± 8.25}{2}$

Solve the fraction

$x= 5 \± 4.125$

Split

$x= 5 + 4.125\ or\ x= 5 - 4.125$

$x= 9.125\ or\ x= 0.875$

7 0

3 years ago

Put together, Dulcina and Tremaine have 129 total matchbooks. Tremaine's collection has 39 fewer matchbooks in it than Dulcina's

Anit [1.1K]

Answer:

Let the Dulcina's collection be 'x'

Let the Tremaine collection be 'x-39'

x + x - 39 =129

2x = 129 +39

2x = 168

x = 168/2

x = 84

Dulcina's collection = x = 84

Tremaine's collection = x - 39 = 84 - 39 = 45

7 0

2 years ago

Sue Mitchell weighed 8 lb. 13 oz. when she was born. She now weighs 93 lb. 5

ra1l [238]

Answer:

Weight gain = 84 lb 5 oz

Average weight gain = 6 lb 5 oz

Step-by-step explanation:

lb means pounds

16 oz = 1 pound

Convert the weight to pounds

Weight when she was born = 8 lb. 13 oz

= 8 pounds + 0.8125 pounds

= 8.8125 pounds

Present weight = 93 lb. 5

= 93 pounds + 0.3125 pounds

= 93.3125 pounds

How much has she gained since birth

Weight gain = Present weight - Weight when she was born

= 93.3125 pounds - 8.8125 pounds

= 84.5 pounds

= 84 lb 5 oz

Weight gain = 84 lb 5 oz

what has been her average weight for each year if she is 13 year old

Average weight gain = Weight gain / 13

= 84.5 pounds / 13

= 6.5 pounds

= 6 lb 5 oz

Average weight gain = 6 lb 5 oz

8 0

2 years ago