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laiz [17]
3 years ago
12

Identify the domain of the equation y = x2 − 6x + 1.

Mathematics
2 answers:
STALIN [3.7K]3 years ago
4 0
\large\begin{array}{l} \textsf{In the following equation}\\\\ \mathsf{y=x^2-6x+1}\\\\ \textsf{x can be any real number (there's no restriction for the domain).}\\\\\\ \textsf{Answer: All real numbers.} \end{array}


If you're having problems understanding the answer, try seeing it through your browser: <span>brainly.com/question/2112553</span>

balu736 [363]3 years ago
4 0

we have

y=x^{2}-6x+1

this is the equation of a vertical parabola open upward

Convert into vertex form

y-1=x^{2}-6x

y-1+9=x^{2}-6x+9

y+8=(x-3)^{2}

y=(x-3)^{2}-8

The vertex is the point (3,-8) ----> is a minimum

The range of the function is the interval--------> [-8,∞)

that means------> all real numbers greater than or equal to -8

The domain of the function is the interval-----> (-∞,∞)

that means------> all real numbers

therefore

<u>the answer is the option</u>

All real numbers

see the attached figure to better understand the problem

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ratelena [41]

Answer:

Obtuse

Step-by-step explanation:

8^2+11^2=14^2\\64+121=196\\185=196

Since the hypotenuse is bigger, the triangle is obtuse

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Step-by-step explanation:

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3 years ago
According to a marketing research study, American teenagers watched 14.8 hours of social media posts per month last year, on ave
ki77a [65]

Answer:

The value of test statistics is 1.06.

Step-by-step explanation:

We are given that according to a marketing research study, American teenagers watched 14.8 hours of social media posts per month last year, on average. A random sample of 11 American teenagers was surveyed and the mean amount of time per month each teenager watched social media posts was 15.6. This data has a sample standard deviation of 2.5.

We have to test if the mean amount of time American teenagers watch social media posts per month is greater than the mean amount of time last year or not.

Let, NULL HYPOTHESIS, H_0 : \mu = 14.8 hours  {means that the mean amount of time American teenagers watch social media posts per month is same as the mean amount of time last year}

ALTERNATE HYPOTHESIS, H_1 : \mu > 14.8 hours  {means that the mean amount of time American teenagers watch social media posts per month is greater than the mean amount of time last year}

The test statistics that will be used here is One-sample t-test;

             T.S. = \frac{\bar X - \mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where, \bar X = sample mean amount of time per month each teenager watched social media posts = 15.6 hours

             s = sample standard deviation = 2.5 hours

             n = sample of teenagers = 11

So, <u>test statistics</u> =  \frac{15.6 - 14.8}{\frac{2.5}{\sqrt{11} } } ~ t_1_0

                            = 1.06

Hence, the value of test statistics is 1.06.

5 0
3 years ago
To solve a system of inequalities so you can graph it how do you change these two equations into something like the two that are
Zigmanuir [339]
Explanation

Problem #2

We must find the solution to the following system of inequalities:

\begin{gathered} 3x-2y\leq4, \\ x+3y\leq6. \end{gathered}

(1) We solve for y the first inequality:

-2y\leq4-3x.

Now, we multiply both sides of the inequality by (-1), this changes the signs on both sides and inverts the inequality symbol:

\begin{gathered} 2y\ge-4+3x, \\ y\ge\frac{3}{2}x-2. \end{gathered}

The solution to this inequality is the set of all the points (x, y) over the line:

y=\frac{3}{2}x-2.

This line has:

• slope m = 3/2,

,

• y-intercept b = -2.

(2) We solve for y the second inequality:

\begin{gathered} x+3y\leq6, \\ 3y\leq6-x, \\ y\leq-\frac{1}{3}x+2. \end{gathered}

The solution to this inequality is the set of all the points (x, y) below the line:

y=-\frac{1}{3}x+2.

This line has:

• slope m = -1/3,

,

• y-intercept b = 2.

(3) Plotting the lines of points (1) and (2), and painting the region:

• over the line from point (1),

,

• and below the line from point (2),

we get the following graph:

Answer

The points that satisfy both inequalities are given by the intersection of the blue and red regions:

8 0
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