Answer: The Median: 78, The First Quartile: 63, and The Third Quartile: 99
Step-by-step explanation: Ok, so let's put the data set from least to greatest....
(63, 63, 76,) (77, 79,) (84, 99, 99)
First Quartile Third Quartile
First, let's find the median, since you made a little mistake...
77 + 79 = 156
156 ÷ 2 = 78
The median is 78!
Now, let's determine the first quartile and the third quartile.
For the the first quartile/third quartile it'll be the middle number, if it's even we'll do the same extra step just like we'll do for the median. In this case it's not even therefore...
First Quartile: 63
Third Quartile: 99
I hope this helps!
<span>b. A linear equation with slope 5 and y-intercept 1 c. A linear equation with slope 2 and y-intercept 3 d. A linear equation with slope 3 and y-intercept 2
</span>
X-int:let y=0
3x-2(0)=18
3x=18
divide both sides by 3
therefore x=6
y-int:let x=0
3(0)-2y=18
-2y=18
we divide both side by -2
therefore y=-9
Answer:
57.6% have allergies
42.4% have no allergies
Step-by-step explanation:
We only need to consider the students who speak two languages according to the question.
To find the percent with allergies, divide the number of students with allergies by the total number of students (that speak two languages).
19/33 = 0.5757 = 57.6%
To find the percent without allergies, divide the number of students without allergies by the total number of students (that speak two languages).
14/33 = 0.4242 = 42.4%
Check your work by adding the percentages to make sure they equal 100%
57.6 + 42.4 = 100
My estimate is about 200$ but I did it in my head so you might want to check on a calculator. :) hope this helped!
