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3 years ago

10

9777-6637-1-5-8-4-1-3-4-4-6

1 answer:

alexandr1967 [171]3 years ago

7 0

Answer:

$3104$

Step-by-step explanation:

$9777-6637-1-5-8-4-1-3-4-4-6$

$=3140-1-5-8-4-1-3-4-4-6$

$=3139-5-8-4-1-3-4-4-6$

$=3134-8-4-1-3-4-4-6$

$=3126-4-1-3-4-4-6$

$=3122-1-3-4-4-6$

$=3121-3-4-4-6$

$=3118-4-4-6$

$=3114-4-6$

$=3110-6$

$=3104$

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Plz help I need it!!!!!!!!!!!!

AlekseyPX

Answer:

114°

Step-by-step explanation:

$? = \frac{1}{2} (53 \degree + 175 \degree) \\ \\ ? = \frac{1}{2} \times 228 \degree\\ \\ ? = 114 \degree$

8 0

3 years ago

You saved $250.00 to spend over the summer. You decide

Ludmilka [50]

Answer:

1 minor thing. you made a mistake it is $25.00 not $25,00. But the answer is this.

Step-by-step explanation:

250.00÷25.00= 10.

4 0

3 years ago

Read 2 more answers

I need help with number 8 please. if you don't mind can you show your work so I know how to do it? Thanks in advance! :)

Trava [24]

You have to divide both sides by 5 because it states"5t" and you should get "t=20"

7 0

3 years ago

Please help I really don’t know what to do

just olya [345]

Answer:

The answer is 0

Step-by-step explanation:

2 * 2 * 2 = 8

8 * 0.5 = 4

4 - 4 = 0

0 / 2 = 0

Make sure the 0.5 is actually 0.5, because it is hard to tell in that expression. if anything, anything, the steps are the same and all you would need to do is the change the numbers.

Hope this helps :)

7 0

3 years ago

<img src="https://tex.z-dn.net/?f=f%28x%29%20-%20%5Cfrac%7Bx%5E%7B2%7D-4%20%7D%7Bx%5E%7B4%7D%20%2Bx%5E%7B3%7D%20-4x%5E%7B2%7D-4%

Llana [10]

a) The given function is

$f(x)=\frac{x^2-4}{x^4+x^3-4x^2-4}$

The domain refers to all values of x for which the function is defined.

The function is defined for

$x^4+x^3-4x^2-4\ne0$

This implies that;

$x\ne -2.69,x\ne 1.83$

b) The vertical asymptotes are x-values that makes the function undefined.

To find the vertical asymptote, equate the denominator to zero and solve for x.

$x^4+x^3-4x^2-4=0$

This implies that;

$x= -2.69,x=1.83$

c) The roots are the x-intercepts of the graph.

To find the roots, we equate the function to zero and solve for x.

$\frac{x^2-4}{x^4+x^3-4x^2-4}=0$

$\Rightarrow x^2-4=0$

$x^2=4$

$x=\pm \sqrt{4}$

$x=\pm2$

The roots are $x=-2,x=2$

d) The y-intercept is where the graph touches the y-axis.

To find the y-inter, we substitute;

$x=0$ into the function

$f(0)=\frac{0^2-4}{0^4+0^3-4(0)^2-4}$

$f(0)=\frac{-4}{-4}=1$

e) to find the horizontal asypmtote, we take limit to infinity

$lim_{x\to \infty}\frac{x^2-4}{x^4+x^3-4x^2-4}=0$

The horizontal asymtote is $y=0$

f) The greatest common divisor of both the numerator and the denominator is 1.

There is no common factor of the numerator and the denominator which is at least a linear factor.

Therefore the function has no holes.

g) The given function is a proper rational function.

There is no oblique asymptote.

See attachment for graph.

6 0

3 years ago