Answer:
9, -3
Step-by-step explanation:
Answer:
15 inches
Step-by-step explanation:
We assume that the edge of the small square is x (inches).
As the edge of the larger square is 2 inches greater than that of the smaller one, so that the edge of the larger square = edge of the small square + 2 = x + 2 (inches)
The equation to calculate the are of a square is: <em>Area = Edge^2 </em>
So that:
+) The area of the larger square is: <em>Area large square = </em>
<em> (square inches)</em>
+) The area of the smaller square is: <em>Area small square = </em>
<em>(square inches)</em>
<em />
As difference in area of both squares are 64 square inches, so that we have:
<em>Area large square - Area small square = 64 (square inches)</em>
<em>=> </em>
<em />
<em>=> </em>
<em />
<em>=> 4x + 4 = 64</em>
<em>=> 4x = 64 - 4 = 60 </em>
<em>=> x = 60/4 = 15 (inches)</em>
So the length of an edge of the smaller square is 15 inches
Answer:
-3/5
Step-by-step explanation:
to figure that out you have to do y^2 - y^1/ x^2 - x^1
2-(-1)/ -3 - 2
= 3/-5
=-3/5
The answer to your problem is 20 inches.