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Eduardwww [97]
3 years ago
5

What is the formula for the area of a sector?

Mathematics
2 answers:
Assoli18 [71]3 years ago
6 0

Answer: A = N/360 x (pi x r^2).

Step-by-step explanation:

looked it up online

CaHeK987 [17]3 years ago
6 0

Answer:

Area of a sector= ½ r² ∅

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Write as an algebraic expression: <br><br> 1) a% of 80 <br><br> 2) 17% of b <br><br> 3) a% of b
Anna35 [415]
1) 4a/5
a% of 80 = a% (80) = (a/100)(80) = 80a/100 = 4a/5

2) 17b/100 or 0.17b
17% of b = (17/100)(b) = 17b/100 [ = 0.17b ]

3) ab/100
a% of b = (a/100)(b) = ab/100
5 0
3 years ago
Pharoah Company had the following adjusted trial balance.
Scrat [10]

Answer:

The solution is given below

Step-by-step explanation:

The preparation of the post closing trial balance is given below

<u>Particulars                 Debit amount         Credit amount</u>

Cash                          $3,820

Account receivable  $4,040

Supplies                    $490

Account payable                                         $1,800

Unearned service revenue                         $180

Owner capital ($4,180 + $5,990 - $1,500 - $390 - $1,700 - $770) $5,810

Salary and wages payable                         $560

Total                    $8,350                            $8,350

4 0
2 years ago
Complete the equation: x2+10x+__=(__)^2 A. 25; x+5 B. 25; x−5 C. 10; x+10 D. 10; x−10
erastovalidia [21]

Answer:

Answer A)  25, and x+5

Step-by-step explanation:

You need to complete the square by adding a constant that makes the quadratic expression a perfect square of a binomial. So base your analysis on the fact that the coefficient accompanying the square term of x is one, and the fact that the middle term has coefficient 10 which is twice "5" so 5 is the likely candidate for the binomial that goes squared: (x + 5) and the square of 5 (25) is what you need to add as constant term to get the perfect square of a binomial:

x^2+10x+25=(x+5)^2

7 0
3 years ago
Solve for y 1/3x+1/4y=2
Zigmanuir [339]

Answer:

y=\frac{-4}{3} x+8

Step-by-step explanation:

Add -1/3x to both sides.

\frac{1}{4}y=\frac{-1}{3}+2

Divide both sides by 1/4.

y=\frac{-4}{3} x+8

hope this helps

6 0
3 years ago
Read 2 more answers
Given: sin = 4/5 and cos x = -5/13 ; evaluate the following expression. Cos 2x
Nitella [24]

For every possible angle x, the fundamental law of trigonometric states that

\sin^2(x)+\cos^2(x) = 1

In your case, the inputs you provided would lead to

\dfrac{16}{25}+\dfrac{25}{169} = \dfrac{3329}{4225} \approx 0.8 \neq 1

So, it is not possible that, for a certain angle x, we have

\sin(x) = \dfrac{4}{5},\quad \cos(x) = -\dfrac{5}{13}

5 0
3 years ago
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