All categories

2 years ago

Answer my question PLEASE

Mathematics

1 answer:

faust18 [17]2 years ago

6 0

Answer:

jahshh83828

Step-by-step explanation:

iwhdbwowhei2kdhe829274

You might be interested in

........................

Ulleksa [173]

Answer:

...................... have no end

Step-by-step explanation:

Hope it will help

<h2>Now , can i get brainlists please</h2>

7 0

2 years ago

Read 2 more answers

Show that the following functions are probability density functions for some value of k and determine k. Then, determine the mea

lord [1]

Answer:

a) 17.5

b) 15.6

c) 13.3

d) 21.51

Step-by-step explanation:

The given function is equal to:

f(x)=kx^2

where

$\int\limits^y_0 {kx^{2} } \, =1$

where y=23

Clearing k=0.00025

a) $Ex=\int\limits^y_0 {xf(x)} \, dx =\int\limits^y_0 {x*0.00025x^{2} } \, dx =17.5$

b) $Vx=Ex^{2} -(Ex)^{2} =\int\limits^y_0 {x^{2}f(x) } \, dx-17.5^{2} =\int\limits^y_0 {x^{2} *0.00025x^{2} } \, dx -17.5^{2} =321.82-306.25=15.6$

c) The function is equal to:

f(x)=k(1+2x)

$\int\limits^y_0 {k(1+2x)} \, =1$

where y=20

k=0.0024

$Ex=\int\limits^y_0 {xf(x)} \, dx =\int\limits^y_0 {x*0.0024(1+2x)} \, dx =13.3$

d) $Vx=Ex^{2} -(Ex)^{2} =\int\limits^y_0 {x^{2} f(x)} \, dx -13.3^{2}=\int\limits^y_0 {x^{2} *0.0024(1+2x)} \, dx-13.3^{2} =198.4-176.89=21.51$

8 0

3 years ago

What are the coordinates of the vertex of the table? Is it a minimum or a maximum?

Anit [1.1K]

The answer would be C.(-2,-3); Minimum.
You can tell be cause the points are going down

3 0

2 years ago

A random sample of 20 houses selected from a city showed that the mean size of these houses is 1880 square feet with a standard

azamat

Answer:

Option C

Step-by-step explanation:

Given that for a random sample of 20 houses selected from a city showed that the mean size of these houses is 1880 square feet with a standard deviation of 320 square feet.

X, the sizes of houses is Normal

Hence sample mean will be normal with

Mean = 1880

and std dev = $\frac{320}{\sqrt{20} } \\=71.5542$

For 90% confidence interval critical value for t with degree of freedom 19 is

1.328

Confidence interval upper bound

= mean + margin of error

= $1880+1.328*71.55\\=1975$

Option C is right

3 0

3 years ago

Solve for X. (Help me please)

Sunny_sXe [5.5K]

The answer is 106.5 by using sin(28) = 50/x

6 0

3 years ago

Read 2 more answers