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Nadya [2.5K]
3 years ago
11

In Carters video game, he needs to score more than 100 points to move on to the next level. Write an inequality to show how many

points Carter needs to earn.
Mathematics
1 answer:
Tresset [83]3 years ago
8 0
You just need to use a variable name to represent the number of points and make it greater than 100.

Use x as the number of the variable, then x has to be greater than 100.

In mathematical language you use the signs >, ≥, < and ≤.

> means greater than

≥ means greater than or equal to

< means less than

≤ means less than or equal to.

Here you need to state that your variable x is greater than 100, that is

x > 100.

That is inequality you wanted.

Answer: x > 100

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Use the ruler to find 1 / 1/10 and 4 1/10
Korvikt [17]

Answer:

the first answer is 10 and the second is 40

Step-by-step explanation:

there actually asking how many meters would make 1 centimeter

On the ruler 1 whole centimeter is 10 meter. (The longer line behind the number is the 10th meter )

Dividing fractions

1 ÷ 1/10

Steps

Change the whole number which is 1 into a fraction.

1/1 ÷1/10

Flip the second fraction in the equation.

1/1 ÷ 10/1

Then change the division sign to a multiplication sign. So were multiply instead.

1/1 × 10/1

Multiply the fractions and your answer should be 10/1 .

This fraction is also changed to a whole number.

10/1 = 10

6 0
2 years ago
A bouquet has 6 roses and 21 other types of flowers. What is the ratio of roses to other flowers?
Andrej [43]

Answer:

6:21

Step-by-step explanation:

because there is 6 roses and 21 other types 6/21 = 6:21

7 0
1 year ago
Read 2 more answers
If anyone knows about definite integrals for calculus then please I request help! I
kicyunya [14]

Answer:

\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{1}{8} \bigg( e^\Big{\frac{4}{25}} - e^\Big{\frac{4}{81}} \bigg)

General Formulas and Concepts:

<u>Calculus</u>

Differentiation

  • Derivatives
  • Derivative Notation

Derivative Property [Multiplied Constant]:                                                           \displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)

Basic Power Rule:

  1. f(x) = cxⁿ
  2. f’(x) = c·nxⁿ⁻¹

Integration

  • Integrals

Integration Rule [Fundamental Theorem of Calculus 1]:                                     \displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)

Integration Property [Multiplied Constant]:                                                         \displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx

U-Substitution

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx

<u>Step 2: Integrate Pt. 1</u>

<em>Identify variables for u-substitution.</em>

  1. Set <em>u</em>:                                                                                                             \displaystyle u = 4x^{-2}
  2. [<em>u</em>] Differentiate [Basic Power Rule, Derivative Properties]:                       \displaystyle du = \frac{-8}{x^3} \ dx
  3. [Bounds] Switch:                                                                                           \displaystyle \left \{ {{x = 9 ,\ u = 4(9)^{-2} = \frac{4}{81}} \atop {x = 5 ,\ u = 4(5)^{-2} = \frac{4}{25}}} \right.

<u>Step 3: Integrate Pt. 2</u>

  1. [Integral] Rewrite [Integration Property - Multiplied Constant]:                 \displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{-1}{8}\int\limits^9_5 {\frac{-8}{x^3}e^\big{4x^{-2}}} \, dx
  2. [Integral] U-Substitution:                                                                              \displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{-1}{8}\int\limits^{\frac{4}{81}}_{\frac{4}{25}} {e^\big{u}} \, du
  3. [Integral] Exponential Integration:                                                               \displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{-1}{8}(e^\big{u}) \bigg| \limits^{\frac{4}{81}}_{\frac{4}{25}}
  4. Evaluate [Integration Rule - Fundamental Theorem of Calculus 1]:           \displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{-1}{8} \bigg( e^\Big{\frac{4}{81}} - e^\Big{\frac{4}{25}} \bigg)
  5. Simplify:                                                                                                         \displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{1}{8} \bigg( e^\Big{\frac{4}{25}} - e^\Big{\frac{4}{81}} \bigg)

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

4 0
2 years ago
Salim says he cannot simplify the expression a^m • a^n. Complete the statement about Salim's claim.
Shkiper50 [21]

Answer:

Salim can simplify that and the answer will be a^m^+^n

Step-by-step explanation:

This is because of the law of multiplying powers, which states that you can add the exponents if the base is the same. So, you just add m and n and put that as the exponent and you will have the answer.

3 0
3 years ago
Read 2 more answers
What is 23,718 rounded to the nearest ten thousand
Allushta [10]
23,718<span>

The 2 is in the ten thousands place. There is a 3 in the thousands place. Since 3 is less than 5, 2 stays the same and everything after it turns into 0s.

20,000

Answer: 20,000</span>
8 0
3 years ago
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