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Andrej [43]
3 years ago
15

The size of an exponentially growing bacteria colony doubles in 8 hours. How long will it take for the number of bacteria to tri

ple? Give your answer in exact form and decimal form.
Mathematics
2 answers:
IRISSAK [1]3 years ago
8 0

Answer:

12.68 hours

Step-by-step explanation:

The population growth function is,

y=ab^{x}

Where,

a = initial population,

b = growth factor per period,

x = number of periods

Here,

y = 2a, x = 8,

2a = a (b)^8

2=b^8

\implies b = 2^\frac{1}{8}

Thus, the function that shows the given situation would be,

y=a(2^\frac{1}{8})^x----(1)

If y = 3a,

3a=a(2^\frac{1}{8})^x

3=(2^\frac{1}{8})^x

\implies x = 12.68

Hence, after 12.68 hours the population would be tripled.

Anna [14]3 years ago
3 0
<span>population ratio to original value is;
=2^(n/8) = 3
=ln[2^(n/8)]
= (n/8)ln(2)
= ln(3)
answer in exact and decimal form
n = 8ln(3)/ln(2)
n ~ 12.68
hope it helps
</span>
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Need answer quickly! thank you in advance!
anyanavicka [17]

Answer:

b)(b²-a²)

Step-by-step explanation:

a cotθ + b cosecθ =p

b cotθ + a cosecθ =q

Now,

p²- q²

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=(acotθ+bcosecθ + bcotθ+ acosecθ) (a cotθ + bcosecθ -bcotθ-acosecθ)

={a(cotθ+cosecθ)+b(cotθ+cosecθ)} {a (cotθ-cosecθ)+b (cosecθ-cotθ)}

={a(cotθ+cosecθ)+b(cotθ+cosecθ)} [a (cotθ-cosecθ) + {- b (cotθ-cosecθ)} ]

={a(cotθ+cosecθ)+b(cotθ+cosecθ)} {a (cotθ-cosecθ) - b (cotθ-cosecθ)}

={(cotθ+cosecθ)(a+b)} {(cotθ-cosecθ) (a-b)}

=(cotθ+cosecθ) (a+b) (cotθ-cosecθ) (a-b)

=(cotθ+cosecθ) (cotθ-cosecθ) (a+b) (a-b)        

= (cot²θ-cosec²θ) (a²-b²)                                 [(a+b) (a-b)= (a²-b²)]

= -1 . (a²-b²)                               [ 1+cot²θ=cosec²θ ; ∴cot²θ-cosec²θ=-1]

=(b²-a²)

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3 years ago
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