Given :
A particle moves in the xy plane starting from time = 0 second and position (1m, 2m) with a velocity of v=2i-4tj .
To Find :
A. The vector position of the particle at any time t .
B. The acceleration of the particle at any time t .
Solution :
A )
Position of vector v is given by :
B )
Acceleration a is given by :
Hence , this is the required solution .
Answer:
Step-by-step explanation:
Eliminating a negative and changing our operation
Rewriting our equation with parts separated
Solving the whole number parts
Solving the fraction parts
Find the LCD of 5/6 and 1/4 and rewrite to solve with the equivalent fractions.
LCD = 12
Combining the whole and fraction parts
[RevyBreeze]
Answer: a) 0.2500
b) 0.1875
c) 0.4375
d) 1.414
e) 0, x/2
f) 1.3333
g) 0.4714
h) 2
Step-by-step explanation: see attachment below
