The scenario can be described using a piecewise function like:
f(x) = 1/x if x < c.
f(x) = x if x = c
f(x) = 1/(x + 73) if x > c.
<h3>
When the value exists but the limit does not?</h3>
Remember that the limit only exists if the limit from left and the limit from the right give the same value.
Then, we can just define a piecewise function of the form:
f(x) = 1/x if x < c.
f(x) = x if x = c
f(x) = 1/(x + 73) if x > c.
Clearly, this is not a continuous function.
Notice that:
So the limits from left and right are different, then:
Does not exist.
If you want to learn more about limits:
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Answer:
20 gallons
Step-by-step explanation:
The living room is made up of white trim and blue surface area between the walls. Since the ratio of the blue surface area between the walls to the white trim is given by 1 : 10.
Also 2 gallons of blue paints are used for the walls, let x represent the number of white paint used in gallons. Hence:
number of white paint in gallons = [1 / (1 + 10)] * total number of paints = 1 / 11 * total number of paints
2 = 1/11 * total number of paints used
total number of paints = 22 gallons
number of white paint (x) = [10 / (1 + 10)] * total number of paints = 1 / 11 * total number of paints
x = 10/11 * 22
x = 20 gallons
Therefore 20 gallons of white paint was used
S = a*((1 - r^(n+1))/(1-r))
S = 1*((1 - 2^(7+1))/(1-2))
S = 1*((1 - 2^8)/(1-2))
S = 1*((1 - 256)/(1-2))
S = 1*((-255)/(-1))
S = 255
So 1+2+4+8+...+128 = 255
Answer:
(10a+5)²= 100 a( a+1) + 25
Step-by-step explanation:
<u><em>Explanation:-</em></u>
Given
(10a+5)²
By using (a+b)² = a² +2ab +b²
= (10a)²+ 2 × 10a× 5 + (5)²
= 100a² + 100a + 25
= 100 a( a+1) + 25
La respuesta de cual es %15 de 400 es 60
