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Furkat [3]
4 years ago
5

Como podria la logica contribuir con la convivencia social

Mathematics
1 answer:
Oksi-84 [34.3K]4 years ago
3 0

Answer:

para mí una lógica es como un motivé un impulso que hace que las personas aspiren e inspiren también trabajen más duro por su objetivo a través del trabajo en equipo también el trabajo en equipo incluye la convivencia social haciendo que puedan convivir juntos

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The city of Easton had a population of 45,000 in 1997 and then began to decrease in population at a rate of 1.5% per year. Which
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45000(1-4.5%) to the 12th power would be 25897 people
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3 years ago
Vince wrote the sequence below.
fgiga [73]
Let's rewrite the given sequence :1/3, 1, 5/3, 7/3 . Notice that 1 =3/3, then

1/3, 3/3, 5/3, 7/3,...We also notice that the common difference d is equal to:
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3 years ago
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A random sample of 144 observations has a mean of 20, a median of 21, and a mode of 22. The population standard deviation is kno
fomenos

Answer: a. 19.200 to 20.800

Step-by-step explanation:

Formula to find the confidence interval(\mu) :-

\overline{x}\pm z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}

, where n is the sample size

\sigma = Population standard deviation.

\overline{x}= Sample mean

z_{\alpha/2} = Two tailed z-value for significance level of \alpha.

Given : Confidence level = 95.44% = 0.9544

Significance level = \alpha=1-0.9544=0.0456

Using standard normal z-value table ,

Two tailed z-value for Significance level of 0.0456 :

z_{\alpha/2}=z_{0.0228}=1.999\approx2

Also,

n=144

\sigma= 4.8

\overline{x}=20

Then, the required 95.44% confidence interval for the population mean :-

20\pm (2)\dfrac{4.8}{\sqrt{144}}\\\\ =20\pm (0.800)\\\\=(20-0.800,\ 20+0.800)=(19.200,\ 20.800)

Hence, the 95.44% confidence interval for the population mean is <u>19.200 to 20.800</u>.

8 0
3 years ago
Question 3 of 10
AlekseyPX

Answer:

x=76°

Step-by-step explanation:

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2 years ago
Which of these expressions or phrases can be used to represent the model choose all the correct answers
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Step-by-step explanation:

anyway.. for your answer i only know that <u>number of fifths in 1</u> is correct I dont know about the rest.

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