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3 years ago

When 4 times a number is increased by 40, the answer is the same as when 100 is decreased by the number. find the number?

1 answer:

8 0

The number is x

4x+40=100-x
add x to both sides
5x+40=100
minus 40 both sides
5x=60
divide both sides by 5
x=12
the number is 12

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Hannah and Anthony are siblings who have ages that are consecutive odd integers. The sum of their

dexar [7]

Answer:

2h-2=92 and h-2=92-h.

Step-by-step explanation:

Hannah, h, is the older sibling and their ages are consecutive odd integers. This means that Anthony's age will be 2 less than Hannah's, or h-2.

The sum of these would be h+(h-2), giving us the equation h+(h-2)=92.

Combining like terms we would have the first correct choice, 2h-2=92.

Our first equation can be transformed, however, to have (h-2) by itself. To do this, we would subtract h from both sides, giving us h-2=92-h.

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3 years ago

Find the slope please

tamaranim1 [39]

Answer:

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Step-by-step explanation:

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2 years ago

Please help and thank you!

bogdanovich [222]

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2 years ago

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Use the following image to assist in your answer.<br> a =<br> - 6<br> - 9<br> - 4

vfiekz [6]

Step-by-step explanation:

Pythagoras' theorem for the smallest one :

$c^2 = 4^2 + 6^2$

$c^2 = 16 + 36$

$c^{2}$ = 52

Pythagoras' theorem for the middle one :

$b^{2}$ = $6^{2}$ + $a^{2}$

Pythagoras' theorem for the biggest one :

$(4+a)^2 = c^2 + b^2$

$16 + 8a + a^2 = 52 + b^2$

Using the formula before (for $b^2$ ) it becomes :

$16 + 8a + a^2 = 52 + (6^2 + a^2)$

$16 + 8a + a^2 = 52 + 6^2 + a^2$

$16 + 8a = 52 + 6^2$

16 + 8a = 52 + 36

16+8a = 88

8a = 88-16

8a = 72

$a = \frac{72}{8}$

a = 9

Verifying :

$b^2 = 6^2 + a^2$

$b^2 = 36 + 81$

$b^2 = 117$

$b^{2}$ = 117

The biggest one :

$(4+a)^2 = c^2 + b^2$

$(4+9)^2 = 52 + 117$

$13^2 = 169$

True

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2 years ago

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max2010maxim [7]

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3 years ago

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