Answer:
x=8 and y=3 (So, yes!)
Step-by-step explanation:
I will solve your system by substitution.
(You can also solve this system by elimination.)
−x+4y=4;−x+3y=1
Step: Solve −x+4y=4 for x:
−x+4y+−4y=4+−4y(Add -4y to both sides)
−x=−4y+4
-x/-1 = -4y+4/-1 (Divide both sides by -1)
x=4y−4
Step: Substitute 4y−4 for x in −x+3y=1:
−x+3y=1
−(4y−4)+3y=1
−y+4=1(Simplify both sides of the equation)
−y+4+−4=1+−4(Add -4 to both sides)
−y=−3
-y/-1 = -3/-1 (Divide both sides by -1)
y=3
Step: Substitute 3 for y in x=4y−4:
=4y−4
x=(4)(3)−4
x=8(Simplify both sides of the equation)
<u>Answer:</u>
x=8 and y=3
Answer:
The solution of |3x-9|≤15 is [-2;8] and the solution |2x-3|≥5 of is (-∞,2] ∪ [8,∞)
Step-by-step explanation:
When solving absolute value inequalities, there are two cases to consider.
Case 1: The expression within the absolute value symbols is positive.
Case 2: The expression within the absolute value symbols is negative.
The solution is the intersection of the solutions of these two cases.
In other words, for any real numbers a and b,
- if |a|> b then a>b or a<-b
- if |a|< b then a<b or a>-b
So, being |3x-9|≤15
Solving: 3x-9 ≤ 15
3x ≤15 + 9
3x ≤24
x ≤24÷3
x≤8
or 3x-9 ≥ -15
3x ≥-15 +9
3x ≥-6
x ≥ (-6)÷3
x ≥ -2
The solution is made up of all the intervals that make the inequality true. Expressing the solution as an interval: [-2;8]
So, being |2x-3|≥5
Solving: 2x-3 ≥ 5
2x ≥ 5 + 3
2x ≥8
x ≥8÷2
x≥8
or 2x-3 ≤ -5
2x ≤-5 +3
2x ≤-2
x ≤ (-2)÷2
x ≤ -2
Expressing the solution as an interval: (-∞,2] ∪ [8,∞)
Answer:
passive income
Step-by-step explanation:
Answer:
it's a
Step-by-step explanation:
just took the testttt
Ok,
f(0.35)= 7f/20
f(-5.2)=-26f/5
f(10)= 10f
f(-0.5)= -f/2
as for the last question I am not quite sure, sorry....hope I helped a little :)
