Answer:
see below
Step-by-step explanation:
(ab)^n=a^n * b^n
We need to show that it is true for n=1
assuming that it is true for n = k;
(ab)^n=a^n * b^n
( ab) ^1 = a^1 * b^1
ab = a * b
ab = ab
Then we need to show that it is true for n = ( k+1)
or (ab)^(k+1)=a^( k+1) * b^( k+1)
Starting with
(ab)^k=a^k * b^k given
Multiply each side by ab
ab * (ab)^k= ab *a^k * b^k
( ab) ^ ( k+1) = a^ ( k+1) b^ (k+1)
Therefore, the rule is true for every natural number n
Answer:
6.28
Step-by-step explanation:
1/2 x 3.14 x 2^2 = 6.28
To solve for 2 variables, you need 2 equations. The best you could do with only one equation would be to find 'a' in terms of 'b'. Just looking it over and without putting pen to paper, it looks to me like one possible solution is [ a = 4, b = 0 ].
Step-by-step explanation:
sorry can't see , Plz click clearly..
