Answer: In-center of the triangle is point N.
Step-by-step explanation:
We are given a triangle △JKL.
In triangle △JKL, they drew perpendicular bisectors of each side of the triangle.
Also we are given angle bisectors of the each of angles in given triangle.
Note: Perpendicular bisector is a line that intersect a segment into two equal parts and also perpendicular to it.
<em>Also note that the in-center is the point forming the origin of a circle inscribed inside the triangle. It is constructed by taking the intersection of the angle bisectors of the three vertices of the triangle.</em>
<h3>We can see that angle bisectors are intersecting at a point N. </h3><h3>
Therefore, in-center of the triangle is point N.</h3>
<u>Answer:</u>
Mid point = 
<u>Step-by-step explanation:</u>
We are given the coordinates of the end points of a line segment AB and we are to find the coordinates of its mid point.
The coordinates of the end points are: A (-1, -2) and B (6, 12).
We know the formula of the mid point:
Mid point = 
So putting in the given values to find the mid point of line segment AB:
Mid point =
= 
Define
g = 9.8 32.2 ft/s², the acceleration due to gravity.
Refer to the diagram shown below.
The initial height at 123 feet above ground is the reference position. Therefore the ground is at a height of - 123 ft, measured upward.
Because the initial upward velocity is - 11 ft/s, the height at time t seconds is
h(t) = -11t - (1/2)gt²
or
h(t) = -11t - 16.1t²
When the ball hits the ground, h = -123.
Therefore
-11t - 16.1t² = -123
11t + 16.1t² = 123
16.1t² + 11t - 123 = 0
t² + 0.6832t - 7.64 = 0
Solve with the quadratic formula.
t = (1/2) [-0.6832 +/- √(0.4668 + 30.56) ] = 2.4435 or -3.1267 s
Reject the negative answer.
The ball strikes the ground after 2.44 seconds.
Answer: 2.44 s