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nexus9112 [7]
3 years ago
9

What is the solution to log (9x)-log 3 = 3?

Mathematics
1 answer:
xeze [42]3 years ago
5 0

Answer:

The solution x = \frac{e^{3} }{3}

Step-by-step explanation:

<u>Step 1</u>:-

Given log(9 x) -log 3 =3

we have to use formula  log a-log b=log\frac{a}{b}

log(9 x)- log 3 = log(\frac{9 x}{3} ) =3

Again by using formula log a =b

                                       a = e^{b}

so \frac{9 x}{3} =e^{3}

<u>step 2:</u>-

   3 x = e^{3}

  x = \frac{e^{3} }{3}

The solution of given problem is x=\frac{e^3}{3}

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HELPP
algol13
I am assuming the both cylinders have the same measure of radius. They only differ in height.

Larger Cylinder = 343 ft³
Smaller Cylinder = 125 ft³ ; height = 5 ft.

We can use proportion for this problem; a:b = c:d where ad = bc

5 ft :125 ft³ = x : 343ft³
5 ft * 343 ft³ = 125 ft³ * x
1715 ft⁴ = 125 ft³ * x
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13.72 ft = x  height of the larger cylinder.

Cone S = 768pi cm³
Cone T = 6144pi cm³ ; height = 24 cm

24 cm : 6144 cm³ = x : 768 cm³
24 cm * 768 cm³ = 6144 cm³ * x
18,432 cm⁴ = 6144 cm³ * x 
18,432 cm⁴ ÷ 6,144 cm³ = x
3 cm = x height of Cone S.



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