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3 years ago

Is 0.09 squared a rational number?

Mathematics

1 answer:

Novay_Z [31]3 years ago

7 0

Yes, 0.09 squared, or 0.0081, is a rational number.

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In the eighth grade 322 students voted for the new mascot to be a tiger this was 7/10 of the total number of students in the eig

Ad libitum [116K]

So first divide by 10 to get 32.2 then multiply by the remaining which is 3/10 so 3. 32.2 times 3 is 96.9 round up 97 add to 322 to get 419.
Your welcome

4 0

4 years ago

Solve the system of linear equations below by graphing. x-y=17 and 3x+y=3

soldier1979 [14.2K]

Answer:

x=5,y=-12

Step-by-step explanation:

You add the two equations to get: 4x=20

Then you get x=5.

You plug this in to x-y=17 to get y=-12

The answer is x=5 and y=-12

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3 years ago

The heights of 40 randomly chosen men are measured and found to follow a normal distribution. An average height of 175 cm is obt

AVprozaik [17]

Answer:

95% two-sided confidence interval for the true mean heights of men is [168.8 cm , 181.2 cm].

Step-by-step explanation:

We are given that the heights of 40 randomly chosen men are measured and found to follow a normal distribution.

An average height of 175 cm is obtained. The standard deviation of men's heights is 20 cm.

Firstly, the pivotal quantity for 95% confidence interval for the true mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample average height = 175 cm

$\sigma$ = population standard deviation = 20 cm

n = sample of men = 40

Here for constructing 95% confidence interval we have used One-sample z test statistics as we know about population standard deviation.

So, 95% confidence interval for the true mean, $\mu$ is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5%

level of significance are -1.96 & 1.96}

P(-1.96 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 1.96) = 0.95

P( $-1.96 \times }{\frac{\sigma}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $1.96 \times }{\frac{\sigma}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-1.96 \times }{\frac{\sigma}{\sqrt{n} } }$ < $\mu$ < $\bar X+1.96 \times }{\frac{\sigma}{\sqrt{n} } }$ ) = 0.95

95% confidence interval for $\mu$ = [ $\bar X-1.96 \times }{\frac{\sigma}{\sqrt{n} } }$ , $\bar X+1.96 \times }{\frac{\sigma}{\sqrt{n} } }$ ]

= [ $175-1.96 \times }{\frac{20}{\sqrt{40} } }$ , $175+1.96 \times }{\frac{20}{\sqrt{40} } }$ ]

= [168.8 cm , 181.2 cm]

Therefore, 95% confidence interval for the true mean height of men is [168.8 cm , 181.2 cm].

The interpretation of the above interval is that we are 95% confident that the true mean height of men will be between 168.8 cm and 181.2 cm.

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3 years ago

17) sove and put the appropriate sign (-40)-(-62) (-62)-(-40) wih explanation q

vaieri [72.5K]

Answer:

q=40

Step-by-step explanation:

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3 years ago

Which set of three numbers could be the side lengths of a triangle?

makvit [3.9K]

Answer:

Step-by-step explanation:

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3 years ago