5*1/5+1/5*15=4
1 + 3 =4
This should equal 4 if I did this correctly.
Answer:
First, determine how many standard deviations above the mean one would have to be to be in the 75th percentile. This can be found by using a z table and finding the z associated with 0.75. The value of z is 0.674. Thus, one must be .674 standard deviations above the mean to be in the 75th percentile
Yep the other one is right it is (4,-2)