All categories

2 years ago

Common factor and HCF of 10m squared,15mk

Mathematics

1 answer:

Anton [14]2 years ago

5 0

Answer:

Step-by-step explanation:

10m^2 and 15mk

common factor is 5m

HCF is 5m

You might be interested in

An automotive technician has two job offers. Shop A would pay him a straight salary of $900 per week. Shop B would pay him $25 p

JulsSmile [24]

Given,

The salary for the technician from shop A is $900 per week.

The salary for the technician from shop B is $25 per hour.

The equation for the total pay for shop B is,

$\text{Total pay= salary of per hour}\times number\text{ of hour worked}$

Taking the total pay as 900. As, to make the shop A and shop B equal.

$\begin{gathered} 900=25\times Number\text{ of hour worked} \\ Number\text{ of hour worked}=\frac{900}{25}=36 \end{gathered}$

Hence, he would have to log 36 hours during a week at Shop B in order to match the salary at Shop A.

7 0

8 months ago

Alex sold 330 candy bars, milk chocolate candy bars sold for $2 each and white chocolate candy bars sold for $3 each. Alex sold

Alinara [238K]

Answer:

<em>Alex sold 330 white chocolate bars</em>

Step-by-step explanation:

let the milk chocolate candy be x and the white chocolate candy be y. then

then 2x+3y=990----1)

x+y=330-----2)

from eq 2) ⇒ x=330-y---------3)

Putting eq 3 in eq 1

2(330-y) +3y=990

660-2y+3y=990

y=990-660=330-----------4)

Putting eq4 in eq1

2x+3(330)=990

2x+990=990

2x=990-990

2x=0

x=0---------------------------5)

4 0

2 years ago

Mary has rehearsed her ballet solo for five and a half hours. A week from now, she wants to have rehearsed at least a total of n

djverab [1.8K]

The answer to this problem is 2

3 0

2 years ago

Read 2 more answers

Suppose JK bisects angle LJM. The measure of angle LJK = (-10x + 3) and the measure of KJM = (-x + 21)º. Find the measure of ang

SpyIntel [72]

<span>LJK = KJM -10x +3 = -x + 21 -10x + x = 21 - 3 -9x = 18 x = -2 KJM = -x + 21 = 2 + 21 = 23 LJM = LJK + KJM LJM = 23 + 23 LJM = 46º..

i think thats how its done </span>

7 0

2 years ago

Jensen is building a snow fort. Each block in the fort weighs about 1 kilogram. Jensen hopes to make about 40 blocks for the for

babymother [125]

Answer: 13,333 snowflakes

Step-by-step explanation:

For this exercise let be "x" represents the number of snowflakes that will be in the fort.

According to the information given in the exercise, the weight of one block is 1 kilogram. Knowing that the fort must have 40 blocks, the total weight is:

$total\ weight=(1\ g)(40)\\\\total\ weight=40\ g$

Since each snowflake weighs $3* 10^{-3}$ grams, need to divide the total weight calculated above by the weight of a snowfake.

Therefore, through this procedure you get the following result:

$x=\frac{40\ grams}{3 * 10 ^{-3}\ grams}\\\\x\approx13,333$

Therefore, the there will be 13,333 snowflakes in the fort.

5 0

2 years ago

Common factor and HCF of 10m squared,15mk​

Common factor and HCF of 10m squared,15mk