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Art [367]
4 years ago
12

Common factor and HCF of 10m squared,15mk​

Mathematics
1 answer:
Anton [14]4 years ago
5 0

Answer:

Step-by-step explanation:

10m^2 and 15mk

common factor is 5m

HCF is 5m

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Which of these numbers had exactly tow factors?
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prime numbers only have two factors...

7 is the only prime in the list

Step-by-step explanation:

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3 years ago
Two different linear functions are shown below with two points given from each function Use slope-intercept form Function A has
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Answer:

This answer is option 1

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
V= 512^2/3* 19683^1/3*256^1/4
irina1246 [14]

Answer:

V=512^2/3* 19683^1/3*256^1/4    = 6912

Step-by-step explanation:

V= (512^{\frac{2}{3} } ) \times (19683^{\frac{1}{3} } )\times  (256^{\frac{1}{4} } )\\

As

2^{9}  = 512\\2^{8} =  256\\19683^{\frac{1}{3} } = 27\\

putting values in equation

V= 2^{9(^{\frac{2}{3} } )} \times 27 \times 2^{8^({\frac{1}{4}) } } \\  let it be equation 1

As

2^9^{\frac{2}{3} }  = 2^6    according\,to\,exponential\,rule\\2^8^\frac{1}{4} =     2^2     according\,to\,exponential\,rule\\\\

putting values in equation 1

V= 2^6\times 27\times 2^2

According to exponential rule 2^6 \times 2^2 = 2^8

V=2^8 \times 27\\

V=256\times 27\\V=6912

So

V= 6912

Keywords: Algebra

Learn more about algebra at:

  • brainly.com/question/3739260
  • brainly.com/question/13168205
  • brainly.com/question/9607945

#learnwithBrainly

7 0
3 years ago
A company’s profit is equal to revenue minus cost. For one company, the yearly revenue is $32 million. What function rule descri
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Let r be the revenue realized in any given year.

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#We notice that the profit, cost or revenue realized in one year is independent of the prior or subsequent year.

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p=r-c\\\\r=32\\\\\therefore p=32-c

Hence, the yearly profit for any given year is expressed as p=32-c (*Units in million $).

6 0
3 years ago
A paper company needs to ship paper to a large printing business. The paper will be shipped in small boxes and large boxes. The
tatyana61 [14]

Answer:a+b

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You can use the variables a and b to solve your equation if you need

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