The sum of n terms of a geometric sequence with first term "a" and common ratio "r" is given by

You have a=21, r=3, so the sum of 10 terms is

The appropriate choice is the 2nd one:
620,004
Answer:
8i+51
Step-by-step explanation:
I'm pretty sure it is just 8i+51 because there isn't really anything you can do with the variable.
Its company 1. if you find the means of all of the company's, company 1 has the biggest mean which means they have the longest commute. So the answer is company 1
Answer:
Rhombus
Step-by-step explanation:
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It is 1.3333333333 repeated