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xenn [34]
3 years ago
14

How do you classify quadrilaterals

Mathematics
2 answers:
timama [110]3 years ago
3 0
Parallelograms, rectangles, rhombus, or square
Travka [436]3 years ago
3 0
Quadrilaterals have four sides and is closed
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A mine elevator was at a depth of -120 feet. After 15 seconds, the mine elevator was at a depth of -30 feet. What expression can
Dafna11 [192]

Answer:

The answers to the given question are:

i.  The equipment elevator is at a depth of 176 feet (-176 feet), while the miner's elevator is at a depth of 210 feet (-210 feet) below the surface.

ii. The miner's elevator is deeper than that of the equipment.

The speed of an object is the rate at which the object moves.

i.e. speed =

Thus,

Speed of the equipment elevator = 4 feet per second

Speed of the miner's elevator = 15 feet per second.

Time of descent of the equipment elevator = 30 + 14

                                 = 44 seconds

So that, the distance of the elevator at this time is;

speed =

⇒ distance = speed x time

                  = 4 x 44

                  = 176

  distance = - 176 feet

The distance of the miner's elevator after 14 seconds is:

speed =

⇒ distance = speed x time

                 = 15 x 14

                 = 210

 distance = - 210 feet

Thus, after another 14 seconds, the equipment elevator is at a depth of 176 feet (-176 feet), while the miner's elevator is at a depth of 210 feet (-210 feet) below the surface.

Therefore, the miner's elevator is deeper than that of the equipment.

Step-by-step explanation:

done

4 0
1 year ago
What is the slope of the line shown below?
liraira [26]

Answer:

C) 3

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
Solve for x use the completing the square method x^2+6x=5
Mrac [35]

Answer:

x_{1} =-3 +\sqrt{14} \\\\x_{2} =-3 -\sqrt{14}

Step-by-step explanation:

x^{2}+6x-5=0

we divide the coefficient of the X by half :

in this case: 6/2 = 3 , then we do the following

The result obtained is raised to square power:  3^2=9

we sum and subtract by 9 to maintain the balance of the equation:

x^{2}+6x+9-9-5=0

we have:

(x+3)^{2}-9-5=0

(x+3)^{2} = 14

lets apply square root on both sides of the equation:

\sqrt{(x+3)^{2}}=\sqrt{14}

we know:

\sqrt{a^{2}} = abs(a)

so we have:

abs(x+3)=\sqrt{14}

from where two solutions are obtained

x_{1} + 3 =\sqrt{14} \\\\x_{2} + 3 =-\sqrt{14}

finally we have:

x_{1} =-3 +\sqrt{14} \\\\x_{2} =-3 -\sqrt{14}

5 0
3 years ago
Read 2 more answers
Find the product of 2/5 with the quotient of 7/3 and 4/5
marissa [1.9K]

Answer:

7/6

Step-by-step explanation:

7/3÷4/5

7/3×5/4

35/12

Now the multiplication

2/5×35/12

70/60

7/6

6 0
2 years ago
The graph of an absolute value function has a vertex at (–2, 3) and passes through the point (–1, 0). Using transformations of t
Law Incorporation [45]

Answer:

The answer to this question can be defined as follows:

Step-by-step explanation:

Given vertex:

(-2,3) and (-1,0)

finding slope:

\bold{Formula:}\\\\\bold{m=\frac{y_2-y_1}{x_2-x_1}}

y_2=0\\y_1=3\\x_2=-1\\x_1=-2

\ M= \frac{0-3}{-2-(-1)}\\\\\ M= \frac{0-3}{-2+1}\\\\\ M= \frac{-3}{-1}\\\\\ M= 3

According to the slope value, its value is greater than 1 that's why the graph has been dilated.

5 0
3 years ago
Read 2 more answers
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